just a punk

See what??? Just replace it with a right number which is 0.6 (you may consider it random if you want) and copy-paste it into http://instacalc.com/ like this:

-25/27 * 0.6 + 8/9

So what's the result? Isn't it 0.3(3)? Isn't 0.3(3) = 1/3 or isn't 0.6 = 3/5?

Feel free to ask more questions if you don't understand something.

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alex_1980

Sorry, but you're wrong.

Put this in instacalc: -25/(27*(5/3)) + 8/9

I forgot the additional brackets but this is correct.

-25
----- <----- this fraction is not the same as this:
27x


-25
---- x
27

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CarlosTheGaucho

are you looking at:

-25/27x or (-25/27)x ?

both options are very simple ..

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CarlosTheGaucho

shit, same second?

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just a punk

No, it's you wrong. Because:

Exactly! Open this post: http://www.gofuckyourself.com/showpo...69&postcount=1 and read the equation. It says: -25/27x which is equal to this:

-25
---- x
27

and IS NOT equal to this

-25
-----
27x

As I suggested above, just use http://instacalc.com/ to understand how exactly the following formula should be calculated: -25/27x

E.g. -25/27*54 = 50 but NOT -0.01714677641. Please don't tell me I'm wrong, just copy-paste the formula into the calculator here: http://instacalc.com/

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just a punk

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

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alex_1980

I will concede that we are both correct and that the problem lies in the syntax of the formula.

I was reading -25/27x as meaning a fraction where 27x was the denominator.
ie: ((-1)(25))/((27)(x))

You read it as just an order of operations: (-1)(25)/(27)(x)

We are therefore both correct based on our own assumptions about the problem.

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CarlosTheGaucho

sorry, this is no equal.. :

(-25)/ (27x) = -25/ 27 . 1/x = -25/27x

(-25/27) . x = -25/27 . x/1 = -25x/27

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Matiz

Syntax Error

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just a punk

Nope, the syntax of formula was absolutely exact. There are no 2 interpretations of -25/27x in math. It's ALWAYS equal to this:
-25
---- x
27

Otherwise it would be written as follows: -25/(27x). It's a main rule of brackets calculation. BTW, that's how ALL the programming languages do process such a formula. -25/27x is always -25 / 27 * x but never -25 / (27 * x)!

E.g.:

/* PHP */
$x = 50;
echo -25 / 27 * $x;

or

/* ANSI/ISO C */
x = 50;
printf("&#37;d\n", -25 / 27 * x);

or

(* ANSI Pascal *)
x := 50;
writeln(-25 / 27 * x);

and so on...

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Matiz

Hm, replace x with any number..

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just a punk

No, just a copy-paste error. I meant this:

-25/27x + 8/9 = 1/3

is a same as

(-25/27) * x + 8/9 = 1/3

and it is a same as

-25 / 27 * x + 8/9 = 1/3

and of course it's not [-25 / (27x)] + 8/9 = 1/3

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CarlosTheGaucho

Yes, but how do you know that Baddog typed it in right?

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sniperwolf

x = 5/3...

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just a punk

Ugh... Why don't they equal? Can you read my post? I believe I wrote there:

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

Did I say anything about (-25)/ (27x)? Please be sure to read before you post a reply

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just a punk

Do you mean if I knew he was sober or not? Course I can't know that for sure. So I assume he was same when he posted the equation. I learned to take it "as is" but not to assume when I doing math calculations

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just a punk

Haven't you seen this post: http://www.gofuckyourself.com/showpo...1&postcount=51 ??? Do you think that 0.6 (3/5) is not "any number"?

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CarlosTheGaucho

And that was the true reason I asked to assure..

I have been studying cybernetics and maths for a while plus I was making some money tutoring maths for a while too, therefore I know that people usually don't know anything about syntax and you have to try to think ahead..

Allright, here is the solution in steps for both cases anyway:

1) -25/27x + 8/9 = 1/3

-25/27 x = 1/3 - 8/9

x = [(1/3 - 8/9) * 27 ] / (- 25)

----------------------------------------


2) (-25)/(27x) + 8/9 = 1/3

(-25)/ (27x) = 1/3 - 8/9

-25 = (1/3 - 8/9) * 27x

-25 / [(1/3 - 8/9)*27] = x


I love to work with numbers ..

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just a punk

Personally I assume that people have at least 3-degree education so they know how to use brackets. Perhaps because we are living in different countries with a way different level of basic (elementary) education

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WiredGuy

Quite the group of mathies on this board, lol.
WG

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CarlosTheGaucho

Yes, ours is in general way better and more demanding than most of the western (meaning in general and till secondary level and not super expensive universities), even not that intelecually gifted people were quite average once they moved abroad as I remember, this is 3rd till 5th grade elementary school if I am not mistaken..

What I am trying to say is that even EVERYONE come through the 5 th grade elementary school there is actually VERY FEW that would know how to use brackets once they are out of the school for a while..

It's absolutely natural and everyone have right to forget stuff he doesn't use, but also SHOULD NOT show off something he forgot..

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Matiz

That post doesn't make this right:

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Emil

If my calculations are correct, the answer is: 15,21

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just a punk

O'rly? That my post says exactly the following:

So you don't agree that -25/27x = (-25/27)x ???

be sure to check it on with a calculator. I.e. copy-paste these formulas into http://instacalc.com/ :
1) -25/27*54
2) (-25/27)*54

Let me know if you'll get a different result with one of the formulas above, professor

Hint: Both -25/27*54 and (-25/27)*54 ARE ABSOLUTELY EQUAL and they both = -50

Furthermore, -25/27 * 0.6 + 8/9 is EQUAL to (-25/27) * 0.6 + 8/9 and it is 1/3 . Surprised?

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just a punk

No, they are not. The answer is 1/3 and it was shown above already.

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Michaelious

Not too difficult an equation.

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martinsc

damn, what's wrong with gfy? i feel like i'm back at highschool... ...
this thread needs some boobie pics ASAP...

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Make Money

D

You guys have done a great job of over complicating a rather simple problem (for a 9th grader).


FYI: you're simply wrong here. The only case where that's true is when x = {-1, 0, 1}; for any other value of x, your equality is false.

[ -25/27x = -25/(27x) ] is the valid statement.

I think it's just a syntax thing at this point - and perhaps (-25/27)x is what baddog meant but you're still wrong in what I quoted. No question there.

Math is an international language, and parentheses are everything in math... if your elementary math instructors taught you otherwise, you'd do well to write the givers of your early education a strongly-worded letter.

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just a punk

4th grader here where I live

Another one... Where are you coming from guys? From a wood?

-25/27x = -25/(27x) is correct.

1) Try this PHP code if you want:

<?php
$x = 54; // some sample value
echo -25/27*$x . " = " . (-25/27)*$x;
?>

You will be surprised when you'll see the result because it will be "-50 = -50"

2) Don't have PHP at your server? Ok, I believe you are able to do this:

a) click at http://instacalc.com/
b) copy-paste this into the calculator's box: -25/27*54
c) remember the result (it will be -50)
d) copy-paste this into the calculator's box: -(25/27)*54
e) remember the result (it will be -50)
f) now compare the results you got in (c) and (e). aren't they equal?

(-25/27)x is baddog meant and it IS what he wrote. because:
(-25/27)*x = -25/27*x (note 2 ways to check it above)

PERIOD.

P.S. x = 54 in both samples and it does not belong to {-1, 0, 1} as you stated above.

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Obey the Cowgod

Matiz

Your syntax is still wrong:

-25/27x is the same as:


-25
----
27x


which you would to type into instacalc as the following:

-25/(27*54)

and what you would get is not -50

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...

Matiz

Math and php code are two different things

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...

just a punk

-25/27x (where x is 54) is the same as:

-25/27*54

and it's a same as:

-25
---- 54
27

and that's you have to type in instacalc.

But(!!!) if you type there -25/(27*54)

it would be

-25
----
27*54

and it would be

-25/(27*x) but NOT -25/27x

Haven't you learn this in the 1st or 2dn degree of preliminary school? What's a funny thread

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just a punk

How many programming languages do you know to make such a statement? Sorry but you're wrong again. PHP as well as all the popular programming languages (C/Pascal/Fortran) use STANDARD MATH CALCULATING MODEL. And please don't tell me that http://instacalc.com/ calculator also uses non-standard math calculating

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Matiz

BTW
Yes, you are absolutely correct



























because you changed the parentheses in the quoted post

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...

just a punk

Are you kidding? Where exactly I changed something? Show me the original post and the one I changed while quoting it.

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Obey the Cowgod

just a punk

1) -25/27x = -25 / 27 * x
2) -25/(27x) = -25 / (27 * x)

Those are different ones. Because (1) <> (2).

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yahoo-xxx-girls.com

-25/27x + 8/9 = 1/3 ( original question )


-25/27x + 24/27 = 1/3 ( find a common denominator in this case 27 )


-1/27x = 1/3 ( do a simple subtraction of -25 + 24 = -1 )


-1/27 / 3/1 = x ( separate the x from the equation... -1/1 = -1 and 27/3 = 9 )


-1/9 = x ( now x has been solved ! )


-1/27 * -1/9 = 1/3 ( now the -1/27x is like saying -1/27 * x or -1/27 * -1/9 )


-1/27 / 9/-1 = 1/3 ( invert to cancel out... -1/-1 = 1 and 27/9 = 3 )


1/3 = 1/3



.

Matiz

No, you didn't change anything while I was quoting it.

But, the part I qouted is quite different from your argument in this thread.



Ok, I have to watch my postcount. I will take a break now.

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...

NetCashBrian

x = 3/5

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CarlosTheGaucho

I guess here at GFY you will find people trolling about anything, if I would put 1 + 1 = 2 it would be more or less the same

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just a punk

Sure it would. For example if I'd like to troll about 1+1=2, I'd ask: "are you sure you typed it correctly?" : Perhaps the second argument was a complex value (say an imaginary 1), so I could assume you meant this:

1 + (0+i1) = 2

which is wrong because the result is also a complex value = 1+i1 <> 2 (since a complex presentation of 2 = 2+i0)

Someone would definitely try to say that 1+i1 = 2, but I will insist that 1+i1 <> 2+i0 and this thread will get at least 3 new pages

j/k

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Semi-Retired-Dave

Story of our lives..

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GrouchyAdmin

0.999 = 1. Hope that helps.

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baddog

I really can't believe this is my first visit to GFY today, and this thread is at the top of page one. Amazing.

Just an FYI, about an hour after I posed the question it was revealed to me that the equation above is the actual question.

For those using decimals, not applicable . . the test is purely fractions, not decimals.

Thanks though.

just a punk

GFY community is studying math these 2 days - a good tendency IMHO

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CarlosTheGaucho

ha ha I KNEW this will happen! beat it - NO COMPLEX VALUES !!

Baddog, listen to the sensible and check no. 68 for a way how to cope with it.. I am off

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goodgirl

It is 8th grade level. So that would be right.

baddog

I will have a spelling test tonight . . stay posted.

just a punk

No, sorry those spelling tests are not for me. I had "3" (an equivalent of your "C") for English when I learned it at the school. So I'll pass that test over

P.S. I had "3" for Math too

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shekinah

This has became a very educational thread.. Never new that there are so many Math genius here

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