Thread: Math question
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Old 09-24-2007, 12:54 PM  
just a punk
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Quote:
Originally Posted by D View Post
You guys have done a great job of over complicating a rather simple problem (for a 9th grader).
4th grader here where I live

Quote:
Originally Posted by D View Post
FYI: you're simply wrong here. The only case where that's true is when x = {-1, 0, 1}; for any other value of x, your equality is false.

[ -25/27x = -25/(27x) ] is the valid statement.
Another one... Where are you coming from guys? From a wood?

-25/27x = -25/(27x) is correct.

1) Try this PHP code if you want:

<?php
$x = 54; // some sample value
echo -25/27*$x . " = " . (-25/27)*$x;
?>

You will be surprised when you'll see the result because it will be "-50 = -50"

2) Don't have PHP at your server? Ok, I believe you are able to do this:

a) click at http://instacalc.com/
b) copy-paste this into the calculator's box: -25/27*54
c) remember the result (it will be -50)
d) copy-paste this into the calculator's box: -(25/27)*54
e) remember the result (it will be -50)
f) now compare the results you got in (c) and (e). aren't they equal?

(-25/27)x is baddog meant and it IS what he wrote. because:
(-25/27)*x = -25/27*x (note 2 ways to check it above)

PERIOD.

P.S. x = 54 in both samples and it does not belong to {-1, 0, 1} as you stated above.
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