Math question - Page 2 - GoFuckYourself.com

just a punk · 09-24-2007, 09:26 AM

Quote:

Originally Posted by hjnet

Replace x with any random number > 1 and see for yourself

See what??? Just replace it with a right number which is 0.6 (you may consider it random if you want) and copy-paste it into http://instacalc.com/ like this:

-25/27 * 0.6 + 8/9

So what's the result? Isn't it 0.3(3)? Isn't 0.3(3) = 1/3 or isn't 0.6 = 3/5?

Feel free to ask more questions if you don't understand something.

alex_1980 · 09-24-2007, 09:43 AM

Quote:

Originally Posted by cyberxxx

See what??? Just replace it with a right number which is 0.6 (you may consider it random if you want) and copy-paste it into instacalc.com like this:

-25/27 * 0.6 + 8/9

So what's the result? Isn't it 0.3(3)? Isn't 0.3(3) = 1/3 or isn't 0.6 = 3/5?

Feel free to ask more questions if you don't understand something.

Sorry, but you're wrong.

Put this in instacalc: -25/(27*(5/3)) + 8/9

I forgot the additional brackets but this is correct.

-25
----- <----- this fraction is not the same as this:
27x

-25
---- x
27

CarlosTheGaucho · 09-24-2007, 09:43 AM

Quote:

Originally Posted by baddog

-25/27x + 8/9 = 1/3

How do I determine what x is?

are you looking at:

-25/27x or (-25/27)x ?

both options are very simple ..

CarlosTheGaucho · 09-24-2007, 09:44 AM

Quote:

Originally Posted by alex_1980

Sorry, but you're wrong.

Put this in instacalc: -25/(27*(5/3)) + 8/9

I forgot the additional brackets but this is correct.

-25
----- <----- this fraction is not the same as this:
27x

-25
---- x
27

shit, same second?

just a punk · 09-24-2007, 09:55 AM

Quote:

Originally Posted by alex_1980

Sorry, but you're wrong.

No, it's you wrong. Because:

Quote:

Originally Posted by alex_1980

-25
----- <----- this fraction is not the same as this:
27x

-25
---- x
27

Exactly! Open this post: http://www.gofuckyourself.com/showpo...69&postcount=1 and read the equation. It says: -25/27x which is equal to this:

-25
---- x
27

and IS NOT equal to this

-25
-----
27x

As I suggested above, just use http://instacalc.com/ to understand how exactly the following formula should be calculated: -25/27x

E.g. -25/27*54 = 50 but NOT -0.01714677641. Please don't tell me I'm wrong, just copy-paste the formula into the calculator here: http://instacalc.com/

just a punk · 09-24-2007, 10:04 AM

Quote:

Originally Posted by CarlosBS

are you looking at:

-25/27x or (-25/27)x ?

both options are very simple ..

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

alex_1980 · 09-24-2007, 10:09 AM

I will concede that we are both correct and that the problem lies in the syntax of the formula.

I was reading -25/27x as meaning a fraction where 27x was the denominator.
ie: ((-1)(25))/((27)(x))

You read it as just an order of operations: (-1)(25)/(27)(x)

We are therefore both correct based on our own assumptions about the problem.

CarlosTheGaucho · 09-24-2007, 10:12 AM

Quote:

Originally Posted by cyberxxx

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

sorry, this is no equal.. :

(-25)/ (27x) = -25/ 27 . 1/x = -25/27x

(-25/27) . x = -25/27 . x/1 = -25x/27

Matiz · 09-24-2007, 10:15 AM

Quote:

Originally Posted by cyberxxx

-25/27x + 8/9 = 1/3

is a same as

(-25/27) * x + 8/9 = 1/3

and it is a same as

-25x / 27x + 8/9 = 1/3

and of course it's not [-25 / (27x)] + 8/9 = 1/3

P.S. The elementary school rules

Syntax Error

just a punk · 09-24-2007, 10:21 AM

Quote:

Originally Posted by alex_1980

I will concede that we are both correct and that the problem lies in the syntax of the formula.

I was reading -25/27x as meaning a fraction where 27x was the denominator.
ie: ((-1)(25))/((27)(x))

You read it as just an order of operations: (-1)(25)/(27)(x)

We are therefore both correct based on our own assumptions about the problem.

Nope, the syntax of formula was absolutely exact. There are no 2 interpretations of -25/27x in math. It's ALWAYS equal to this:
-25
---- x
27

Otherwise it would be written as follows: -25/(27x). It's a main rule of brackets calculation. BTW, that's how ALL the programming languages do process such a formula. -25/27x is always -25 / 27 * x but never -25 / (27 * x)!

E.g.:

/* PHP */
$x = 50;
echo -25 / 27 * $x;

or

/* ANSI/ISO C */
x = 50;
printf("%d\n", -25 / 27 * x);

or

(* ANSI Pascal *)
x := 50;
writeln(-25 / 27 * x);

and so on...

Matiz · 09-24-2007, 10:21 AM

Quote:

Originally Posted by cyberxxx

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

Hm, replace x with any number..

just a punk · 09-24-2007, 10:24 AM

Quote:

Originally Posted by Matiz

Syntax Error

No, just a copy-paste error. I meant this:

-25/27x + 8/9 = 1/3

is a same as

(-25/27) * x + 8/9 = 1/3

and it is a same as

-25 / 27 * x + 8/9 = 1/3

and of course it's not [-25 / (27x)] + 8/9 = 1/3

CarlosTheGaucho · 09-24-2007, 10:24 AM

Quote:

Originally Posted by cyberxxx

Nope, the syntax of formula was absolutely exact. There are no 2 interpretations of -25/27x in math. It's ALWAYS equal to this:
-25
---- x
27

Yes, but how do you know that Baddog typed it in right?

sniperwolf · 09-24-2007, 10:27 AM

x = 5/3...

just a punk · 09-24-2007, 10:28 AM

Quote:

Originally Posted by CarlosBS

sorry, this is no equal.. :

(-25)/ (27x) = -25/ 27 . 1/x = -25/27x

(-25/27) . x = -25/27 . x/1 = -25x/27

Ugh... Why don't they equal? Can you read my post? I believe I wrote there:

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

Did I say anything about (-25)/ (27x)? Please be sure to read before you post a reply

just a punk · 09-24-2007, 10:33 AM

Quote:

Originally Posted by CarlosBS

Yes, but how do you know that Baddog typed it in right?

Do you mean if I knew he was sober or not?

Course I can't know that for sure. So I assume he was same when he posted the equation. I learned to take it "as is" but not to assume when I doing math calculations

just a punk · 09-24-2007, 10:35 AM

Quote:

Originally Posted by Matiz

Hm, replace x with any number..

Haven't you seen this post: http://www.gofuckyourself.com/showpo...1&postcount=51 ??? Do you think that 0.6 (3/5) is not "any number"?

CarlosTheGaucho · 09-24-2007, 10:43 AM

Quote:

Originally Posted by cyberxxx

Do you mean if I knew he was sober or not?

Course I can't know that for sure. So I assume he was same when he posted the equation. I learned to take it "as is" but not to assume when I doing math calculations

And that was the true reason I asked to assure..

I have been studying cybernetics and maths for a while plus I was making some money tutoring maths for a while too, therefore I know that people usually don't know anything about syntax and you have to try to think ahead..

Allright, here is the solution in steps for both cases anyway:

1) -25/27x + 8/9 = 1/3

-25/27 x = 1/3 - 8/9

x = [(1/3 - 8/9) * 27 ] / (- 25)

----------------------------------------

2) (-25)/(27x) + 8/9 = 1/3

(-25)/ (27x) = 1/3 - 8/9

-25 = (1/3 - 8/9) * 27x

-25 / [(1/3 - 8/9)*27] = x

I love to work with numbers ..

just a punk · 09-24-2007, 10:49 AM

Quote:

Originally Posted by CarlosBS

I have been studying cybernetics and maths for a while plus I was making some money tutoring maths for a while too, therefore I know that people usually don't know anything about syntax and you have to try to think ahead..

Personally I assume that people have at least 3-degree education so they know how to use brackets. Perhaps because we are living in different countries with a way different level of basic (elementary) education

WiredGuy · 09-24-2007, 11:03 AM

Quite the group of mathies on this board, lol.
WG

CarlosTheGaucho · 09-24-2007, 11:06 AM

Quote:

Originally Posted by cyberxxx

Personally I assume that people have at least 3-degree education so they know how to use brackets. Perhaps because we are living in different countries with a way different level of basic (elementary) education

Yes, ours is in general way better and more demanding than most of the western (meaning in general and till secondary level and not super expensive universities), even not that intelecually gifted people were quite average once they moved abroad as I remember, this is 3rd till 5th grade elementary school if I am not mistaken..

What I am trying to say is that even EVERYONE come through the 5 th grade elementary school there is actually VERY FEW that would know how to use brackets once they are out of the school for a while..

It's absolutely natural and everyone have right to forget stuff he doesn't use, but also SHOULD NOT show off something he forgot..

Matiz · 09-24-2007, 11:19 AM

Quote:

Originally Posted by cyberxxx

Haven't you seen this post: http://www.gofuckyourself.com/showpo...1&postcount=51 ??? Do you think that 0.6 (3/5) is not "any number"?

That post doesn't make this right:

Quote:

Originally Posted by cyberxxx

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

Emil · 09-24-2007, 11:27 AM

If my calculations are correct, the answer is: 15,21

just a punk · 09-24-2007, 11:51 AM

Quote:

Originally Posted by Matiz

Quote:

Originally Posted by cyberxxx View Post
Haven't you seen this post: http://www.gofuckyourself.com/showpo...1&postcount=51 ??? Do you think that 0.6 (3/5) is not "any number"?

That post doesn't make this right:

Quote:

Originally Posted by cyberxxx View Post
Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

O'rly?

That my post says exactly the following:

Quote:

See what??? Just replace it with a right number which is 0.6 (you may consider it random if you want) and copy-paste it into http://instacalc.com/ like this:

-25/27 * 0.6 + 8/9

So what's the result? Isn't it 0.3(3)? Isn't 0.3(3) = 1/3 or isn't 0.6 = 3/5?

Feel free to ask more questions if you don't understand something.

So you don't agree that -25/27x = (-25/27)x ???

be sure to check it on with a calculator. I.e. copy-paste these formulas into http://instacalc.com/ :
1) -25/27*54
2) (-25/27)*54

Let me know if you'll get a different result with one of the formulas above, professor

Hint: Both -25/27*54 and (-25/27)*54 ARE ABSOLUTELY EQUAL and they both = -50

Furthermore, -25/27 * 0.6 + 8/9 is EQUAL to (-25/27) * 0.6 + 8/9 and it is 1/3 . Surprised?

just a punk · 09-24-2007, 12:21 PM

Quote:

Originally Posted by Emil

If my calculations are correct, the answer is: 15,21

No, they are not. The answer is 1/3 and it was shown above already.

Michaelious · 09-24-2007, 12:23 PM

Not too difficult an equation.

martinsc · 09-24-2007, 12:32 PM

damn, what's wrong with gfy? i feel like i'm back at highschool...

...
this thread needs some boobie pics ASAP...

D · 09-24-2007, 12:39 PM

You guys have done a great job of over complicating a rather simple problem (for a 9th grader).

Quote:

Originally Posted by cyberxxx

Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x

FYI: you're simply wrong here. The only case where that's true is when x = {-1, 0, 1}; for any other value of x, your equality is false.

[ -25/27x = -25/(27x) ] is the valid statement.

I think it's just a syntax thing at this point - and perhaps (-25/27)x is what baddog meant but you're still wrong in what I quoted. No question there.

Math is an international language, and parentheses are everything in math... if your elementary math instructors taught you otherwise, you'd do well to write the givers of your early education a strongly-worded letter.

just a punk · 09-24-2007, 12:54 PM

Quote:

Originally Posted by D

You guys have done a great job of over complicating a rather simple problem (for a 9th grader).

4th grader here where I live

Quote:

Originally Posted by D

FYI: you're simply wrong here. The only case where that's true is when x = {-1, 0, 1}; for any other value of x, your equality is false.

[ -25/27x = -25/(27x) ] is the valid statement.

Another one...

Where are you coming from guys? From a wood?

-25/27x = -25/(27x) is correct.

1) Try this PHP code if you want:

<?php
$x = 54; // some sample value
echo -25/27*$x . " = " . (-25/27)*$x;
?>

You will be surprised when you'll see the result because it will be "-50 = -50"

2) Don't have PHP at your server? Ok, I believe you are able to do this:

a) click at http://instacalc.com/
b) copy-paste this into the calculator's box: -25/27*54
c) remember the result (it will be -50)
d) copy-paste this into the calculator's box: -(25/27)*54
e) remember the result (it will be -50)
f) now compare the results you got in (c) and (e). aren't they equal?

(-25/27)x is baddog meant and it IS what he wrote. because:
(-25/27)*x = -25/27*x (note 2 ways to check it above)

PERIOD.

P.S. x = 54 in both samples and it does not belong to {-1, 0, 1} as you stated above.

Matiz · 09-24-2007, 12:55 PM

Quote:

Originally Posted by cyberxxx

O'rly?

That my post says exactly the following:

So you don't agree that -25/27x = (-25/27)x ???

be sure to check it on with a calculator. I.e. copy-paste these formulas into http://instacalc.com/ :
1) -25/27*54
2) (-25/27)*54

Let me know if you'll get a different result with one of the formulas above, professor

Hint: Both -25/27*54 and (-25/27)*54 ARE ABSOLUTELY EQUAL and they both = -50

Furthermore, -25/27 * 0.6 + 8/9 is EQUAL to (-25/27) * 0.6 + 8/9 and it is 1/3 . Surprised?

Your syntax is still wrong:

-25/27x is the same as:

-25
----
27x

which you would to type into instacalc as the following:

-25/(27*54)

and what you would get is not -50

Matiz · 09-24-2007, 01:04 PM

Quote:

Originally Posted by cyberxxx

1) Try this PHP code if you want:

<?php
$x = 54; // some sample value
echo -25/27*$x . " = " . (-25/27)*$x;
?>

You will be surprised when you'll see the result because it will be "-50 = -50"

Math and php code are two different things

just a punk · 09-24-2007, 01:04 PM

Quote:

Originally Posted by Matiz

Your syntax is still wrong:

-25/27x is the same as:

-25
----
27x

which you would to type into instacalc as the following:

-25/(27*54)

and what you would get is not -50

-25/27x (where x is 54) is the same as:

-25/27*54

and it's a same as:

-25
---- 54
27

and that's you have to type in instacalc.

But(!!!) if you type there -25/(27*54)

it would be

-25
----
27*54

and it would be

-25/(27*x) but NOT -25/27x

Haven't you learn this in the 1st or 2dn degree of preliminary school? What's a funny thread

just a punk · 09-24-2007, 01:09 PM

Quote:

Originally Posted by Matiz

Math and php code are two different things

How many programming languages do you know to make such a statement? Sorry but you're wrong again. PHP as well as all the popular programming languages (C/Pascal/Fortran) use STANDARD MATH CALCULATING MODEL. And please don't tell me that http://instacalc.com/ calculator also uses non-standard math calculating

Matiz · 09-24-2007, 01:10 PM

Quote:

Originally Posted by cyberxxx

-25/27x = -25/(27x) is correct.

BTW
Yes, you are absolutely correct

because you changed the parentheses in the quoted post

just a punk · 09-24-2007, 01:14 PM

Quote:

Originally Posted by Matiz

BTW
Yes, you are absolutely correct

because you changed the parentheses in the quoted post

Are you kidding? Where exactly I changed something? Show me the original post and the one I changed while quoting it.

just a punk · 09-24-2007, 01:17 PM

1) -25/27x = -25 / 27 * x
2) -25/(27x) = -25 / (27 * x)

Those are different ones. Because (1) <> (2).

yahoo-xxx-girls.com · 09-24-2007, 01:36 PM

-25/27x + 8/9 = 1/3 ( original question )

-25/27x + 24/27 = 1/3 ( find a common denominator in this case 27 )

-1/27x = 1/3 ( do a simple subtraction of -25 + 24 = -1 )

-1/27 / 3/1 = x ( separate the x from the equation... -1/1 = -1 and 27/3 = 9 )

-1/9 = x ( now x has been solved ! )

-1/27 * -1/9 = 1/3 ( now the -1/27x is like saying -1/27 * x or -1/27 * -1/9 )

-1/27 / 9/-1 = 1/3 ( invert to cancel out... -1/-1 = 1 and 27/9 = 3 )

1/3 = 1/3

.

Matiz · 09-24-2007, 02:15 PM

Quote:

Originally Posted by cyberxxx

Are you kidding? Where exactly I changed something? Show me the original post and the one I changed while quoting it.

No, you didn't change anything while I was quoting it.

But, the part I qouted is quite different from your argument in this thread.

Ok, I have to watch my postcount. I will take a break now.

NetCashBrian · 09-24-2007, 02:27 PM

x = 3/5

CarlosTheGaucho · 09-24-2007, 02:47 PM

Quote:

Originally Posted by D

You guys have done a great job of over complicating a rather simple problem (for a 9th grader).

I guess here at GFY you will find people trolling about anything, if I would put 1 + 1 = 2 it would be more or less the same

just a punk · 09-24-2007, 04:15 PM

Quote:

Originally Posted by CarlosBS

I guess here at GFY you will find people trolling about anything, if I would put 1 + 1 = 2 it would be more or less the same

Sure it would. For example if I'd like to troll about 1+1=2, I'd ask: "are you sure you typed it correctly?" :

Perhaps the second argument was a complex value (say an imaginary 1), so I could assume you meant this:

1 + (0+i1) = 2

which is wrong because the result is also a complex value = 1+i1 <> 2 (since a complex presentation of 2 = 2+i0)

Someone would definitely try to say that 1+i1 = 2, but I will insist that 1+i1 <> 2+i0 and this thread will get at least 3 new pages

j/k

Semi-Retired-Dave · 09-24-2007, 04:16 PM

Quote:

Originally Posted by tony404

I had to take Algebra twice sorry no help here but my wife is a wiz let me get her.

Story of our lives..

GrouchyAdmin · 09-24-2007, 04:20 PM

0.999 = 1. Hope that helps.

baddog · 09-24-2007, 04:20 PM

Quote:

Originally Posted by alex_1980

-25
---- x
27

I really can't believe this is my first visit to GFY today, and this thread is at the top of page one. Amazing.

Just an FYI, about an hour after I posed the question it was revealed to me that the equation above is the actual question.

For those using decimals, not applicable . . the test is purely fractions, not decimals.

Thanks though.

just a punk · 09-24-2007, 04:27 PM

Quote:

Originally Posted by baddog

I really can't believe this is my first visit to GFY today, and this thread is at the top of page one. Amazing.

GFY community is studying math these 2 days - a good tendency IMHO

CarlosTheGaucho · 09-24-2007, 04:29 PM

Quote:

Originally Posted by cyberxxx

Sure it would. For example if I'd like to troll about 1+1=2, I'd ask: "are you sure you typed it correctly?" :

Perhaps the second argument was a complex value (say an imaginary 1), so I could assume you meant this:

1 + (0+i1) = 2

which is wrong because the result is also a complex value = 1+i1 <> 2 (since a complex presentation of 2 = 2+i0)

Someone would definitely try to say that 1+i1 = 2, but I will insist that 1+i1 <> 2+i0 and this thread will get at least 3 new pages

j/k

ha ha I KNEW this will happen! beat it - NO COMPLEX VALUES !!

Baddog, listen to the sensible and check no. 68 for a way how to cope with it.. I am off

goodgirl · 09-24-2007, 04:30 PM

Quote:

Originally Posted by hjnet

I 2nd that, although I'd say it would need a 12-13 year old non-retarded child IMHO.

It is 8th grade level. So that would be right.

baddog · 09-24-2007, 04:31 PM

Quote:

Originally Posted by cyberxxx

GFY community is studying math these 2 days - a good tendency IMHO

I will have a spelling test tonight . . stay posted.

just a punk · 09-24-2007, 04:39 PM

Quote:

Originally Posted by baddog

I will have a spelling test tonight . . stay posted.

No, sorry those spelling tests are not for me. I had "3" (an equivalent of your "C") for English when I learned it at the school. So I'll pass that test over

P.S. I had "3" for Math too

shekinah · 09-24-2007, 04:45 PM

This has became a very educational thread.. Never new that there are so many Math genius here

09-24-2007, 10:09 AM	#57
alex_1980 Registered User Join Date: Jan 2007 Location: Moncton, NB Posts: 52	I will concede that we are both correct and that the problem lies in the syntax of the formula. I was reading -25/27x as meaning a fraction where 27x was the denominator. ie: ((-1)(25))/((27)(x)) You read it as just an order of operations: (-1)(25)/(27)(x) We are therefore both correct based on our own assumptions about the problem. __________________ ICQ: 367-726-824

09-24-2007, 10:27 AM	#64
sniperwolf Too lazy to set a custom title Join Date: Mar 2005 Posts: 17,743	x = 5/3... __________________ ~Accepting design works~

09-24-2007, 11:03 AM	#70
WiredGuy Pounding Googlebot Industry Role: Join Date: Aug 2002 Location: Canada Posts: 34,496	Quite the group of mathies on this board, lol. WG __________________ I play with Google.

09-24-2007, 11:27 AM	#73
Emil Confirmed User Join Date: Feb 2007 Location: Sweden Posts: 5,651	If my calculations are correct, the answer is: 15,21 __________________ Free 🅑🅘🅣🅒🅞🅘🅝🅢 Every Hour (Yes, really. Free ₿itCoins.) (Signup with ONLY your Email and Password. You can also refer people and get even more.)

09-24-2007, 12:23 PM	#76
Michaelious Confirmed User Join Date: Jan 2004 Location: Scotland Posts: 6,720	Not too difficult an equation. __________________

09-24-2007, 12:32 PM	#77
martinsc Too lazy to set a custom title Industry Role: Join Date: Jun 2005 Location: 127.0.0.1 Posts: 27,047	damn, what's wrong with gfy? i feel like i'm back at highschool... ... this thread needs some boobie pics ASAP... __________________ Make Money

09-24-2007, 01:17 PM	#86
just a punk So fuckin' bored Industry Role: Join Date: Jun 2003 Posts: 32,386	1) -25/27x = -25 / 27 * x 2) -25/(27x) = -25 / (27 * x) Those are different ones. Because (1) <> (2). __________________ Obey the Cowgod

09-24-2007, 01:36 PM	#87
yahoo-xxx-girls.com Confirmed User Join Date: Jul 2006 Location: Canada Posts: 3,143	Simple people ! -25/27x + 8/9 = 1/3 ( original question ) -25/27x + 24/27 = 1/3 ( find a common denominator in this case 27 ) -1/27x = 1/3 ( do a simple subtraction of -25 + 24 = -1 ) -1/27 / 3/1 = x ( separate the x from the equation... -1/1 = -1 and 27/3 = 9 ) -1/9 = x ( now x has been solved ! ) *-1/27 -1/9 = 1/3** ( now the -1/27x is like saying -1/27 x or -1/27 * -1/9 )* -1/27 / 9/-1 = 1/3 ( invert to cancel out... -1/-1 = 1 and 27/9 = 3 ) 1/3 = 1/3 .

09-24-2007, 02:27 PM	#89
NetCashBrian Confirmed User Join Date: Feb 2007 Posts: 295	x = 3/5 __________________ NetCash Brian Chief Operating Officer ICQ: 334-743-934 Email: [email protected]

09-24-2007, 04:20 PM	#93
GrouchyAdmin Now choke yourself! Industry Role: Join Date: Apr 2006 Posts: 12,085	0.999 = 1. Hope that helps. __________________ AIM: GrouchyGfy

09-24-2007, 04:45 PM	#100
shekinah Confirmed User Join Date: May 2006 Posts: 8,452	This has became a very educational thread.. Never new that there are so many Math genius here __________________ [Web Design \| Development \| Programming \| Content Writing ] ICQ: 238-890-469