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Welcome to the GoFuckYourself.com - Adult Webmaster Forum forums. You are currently viewing our boards as a guest which gives you limited access to view most discussions and access our other features. By joining our free community you will have access to post topics, communicate privately with other members (PM), respond to polls, upload content and access many other special features. Registration is fast, simple and absolutely free so please, join our community today! If you have any problems with the registration process or your account login, please contact us. |
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| Discuss what's fucking going on, and which programs are best and worst. One-time "program" announcements from "established" webmasters are allowed. |
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10-06-2004, 01:54 AM
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#51 |
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Too lazy to set a custom title
Industry Role:
Join Date: Oct 2001
Location: ┌∩┐ ◣_◢ ┌∩┐
Posts: 46,909
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50 Panamanian hookers.
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10-06-2004, 02:05 AM
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#52 | |
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Let's do some business.
Industry Role:
Join Date: Jan 2003
Location: The dirty south.
Posts: 18,781
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Quote:
http://www.google.com/search?sourcei...&q=12+choose+3
__________________
 Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be." |
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10-06-2004, 02:09 AM
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#53 | |
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Confirmed User
Join Date: May 2002
Location: European Union
Posts: 3,815
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Quote:
Or just imagine 4 Girls, to make it simplier let's call them A;B;C and D. To group them in groups of 3 so that each girl is ounce with each other you'd have to make the following combinations ABC; DAB and DC?. So you'd only need to make 3 combinations and you still have one place left for an additional girl (so you can save a few combinations if you group them smart) With your calculation you'd need 4 combinations. If you take 5 Girls A;B;C;D;E then you'd need ABC; DAB; EAB and ECD, 4 combinations, not 10 as with your calculation. So I don't know what you've calculated there, but 220 isn't right. But I have to say that I can't mathematical proof my own number of combinations (34) at this time and it might be possible that I'm wrong too, but I can give you some kind of "circumstantial evidence" If you'd just have that you'd have to group in groups of random 3 then you'd have with: 3 Girls, 1 combination neccessary 4 Girls, 3 combinations neccessary 5 Girls, 5 combinations neccessary 6 Girls, 8 combinations neccessary 7 Girls, 11 combinations neccessary 8 Girls, 15 combinations neccessary 9 Girls, 19 combinations neccessary 10 Girls, 24 combinations neccessary 11 Girls, 29 combinations neccessary 12 Girls, 35 combinations neccessary If you can group them in a smart way you can save a few combinations: 3 Girls, 1 combination neccessary 4 Girls, 3 combinations neccessary 5 Girls, 4 combinations neccessary 6 Girls, 7 combinations neccessary 7 Girls, 9 combinations neccessary 8 Girls, 13 combinations neccessary 9 Girls, 16 combinations neccessary 10 Girls, 21 combinations neccessary 11 Girls, 27 combinations neccessary 12 Girls, 33 combinations neccessary  |
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10-06-2004, 02:12 AM
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#54 | |
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Let's do some business.
Industry Role:
Join Date: Jan 2003
Location: The dirty south.
Posts: 18,781
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Quote:
__________________
Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be." |
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10-06-2004, 02:20 AM
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#55 |
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Let's do some business.
Industry Role:
Join Date: Jan 2003
Location: The dirty south.
Posts: 18,781
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hj,
Gonna pretend you aren't joking and post this. The answer is 220. Here are the first 55 combinations if you number the girls 1 through 12. 1 2 3 1 2 4 1 2 5 1 2 6 1 2 7 1 2 8 1 2 9 1 2 10 1 2 11 1 2 12 1 3 4 1 3 5 1 3 6 1 3 7 1 3 8 1 3 9 1 3 10 1 3 11 1 2 12 1 4 5 1 4 6 1 4 7 1 4 8 1 4 9 1 4 10 1 4 11 1 4 12 1 5 6 1 5 7 1 5 8 1 5 9 1 5 10 1 5 11 1 5 12 1 6 7 1 6 8 1 6 9 1 6 10 1 6 11 1 6 12 1 7 8 1 7 9 1 7 10 1 7 11 1 7 12 1 8 9 1 8 10 1 8 11 1 8 12 1 9 10 1 9 11 1 9 12 1 10 11 1 10 12 1 11 12
__________________
Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be." |
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10-06-2004, 02:54 AM
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#56 | |
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Confirmed User
Join Date: May 2002
Location: European Union
Posts: 3,815
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Quote:
1 2 3 1 4 5 1 6 7 1 8 9 1 10 11 1 12 ? In your example girl 1 is blowing 10 times together with girl 2, 9 times with girl 3 etc, I don't think Steve wants to waste his time :-) |
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10-06-2004, 02:59 AM
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#57 | |
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Die With Your Boots On
Join Date: Oct 2003
Location: Hawaii
Posts: 22,872
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Quote:
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10-06-2004, 03:02 AM
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#58 | |
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FUBAR the ORIGINATOR
Industry Role:
Join Date: Jan 2002
Location: FUBARLAND
Posts: 67,374
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Quote:
__________________
 FUBAR Webmasters - The FUBAR Times - FUBAR Webmasters Mobile - FUBARTV.XXX For promo opps contact jfk at fubarwebmasters dot com |
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10-06-2004, 03:09 AM
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#59 | |
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Let's do some business.
Industry Role:
Join Date: Jan 2003
Location: The dirty south.
Posts: 18,781
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Quote:
__________________
Hands Free Adult - Join Once, Earn For Life "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be." |
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10-06-2004, 03:35 AM
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#60 |
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Confirmed User
Industry Role:
Join Date: Jul 2003
Posts: 3,108
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This thread shows how many high school kids we have here ;)
Anyway, question is not really formulated well... is it 2 or 3 girls and if its 3 do you want every possible combination or just each girl with 2 different ones but never repeating any of the 2 you already had?
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"Think about it a little more and you'll agree with me, because you're smart and I'm right." - Charlie Munger |
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10-06-2004, 05:06 AM
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#61 |
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Confirmed User
Join Date: Jul 2001
Location: Lightspeedworld
Posts: 7,940
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ok here is the correct answer:
12 girls giving triple blowjobs in every possible combination with each of the other girls = one very sore little red nub where my dick used to be. "NO MORE YANKY MY WANKY!!!" I'm headed home now. End of the Panamanian Adventure Weekend for me. Steve Lightspeed
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Abra-cadabra! |
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10-06-2004, 09:31 AM
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#62 | |
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Confirmed User
Join Date: Nov 2003
Location: 237 619 975
Posts: 8,944
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Quote:
Ok you math skils arent terrible, you are wrong because you mis interpreted the question. You are wrong, the guy who listed the first 55 combos is right.
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10-06-2004, 09:40 AM
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#63 |
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Too lazy to set a custom title
Industry Role:
Join Date: Mar 2003
Location: Homeless
Posts: 62,911
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I shot the cat on this one.
Thank god it waS NOT my cat. I think it belongs to the people next door., Oh well.
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PornGuy skype me pornguy_epic AmateurDough The Hottes Shemales online! TChicks.com | Angeles Cid | Mariana Cordoba | MAILERS WELCOME! |
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10-06-2004, 11:28 AM
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#64 |
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Pounding Googlebot
Industry Role:
Join Date: Aug 2002
Location: Canada
Posts: 34,486
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I can't believe this thread is still going on, lol.
WG
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I play with Google. |
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