Quote:
Originally posted by hjnet
Steve want's "each girl to perform one triple blowjob with each of the other girls" which means to me that each girl only have to be ONCE with another, so as I see it you don't have to make 55 attempts to group the first girl with each other of the remaining 11 you' only have to make 6 combinations.
1 2 3
1 4 5
1 6 7
1 8 9
1 10 11
1 12 ?
In your example girl 1 is blowing 10 times together with girl 2, 9 times with girl 3 etc, I don't think Steve wants to waste his time :-)
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Ok you math skils arent terrible, you are wrong because you mis interpreted the question.
You are wrong, the guy who listed the first 55 combos is right.