embedding CSS in PHP, example, please look - GoFuckYourself.com

Kard63 · 02-06-2007, 07:24 PM

print "<IMG STYLE="position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px" SRC="hair$hair.gif">";

Whats wrong with that line? thanks.

Chio · 02-06-2007, 07:25 PM

Quote:

Originally Posted by Kard63

print "<IMG STYLE="position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px" SRC="hair$hair.gif">";

Whats wrong with that line? thanks.

I'm not a coder at all but maybe you need to escape out some of those characters?

Kard63 · 02-06-2007, 07:27 PM

the line:

print "<img src = hair$hair.gif>";

works. but when I try to add CSS it goes to shit.

DjSap · 02-06-2007, 07:29 PM

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

naitirps · 02-06-2007, 07:30 PM

try this:

echo "<IMG STYLE=\"position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px\" SRC=\"hair".$hair.".gif\">";

Kard63 · 02-06-2007, 07:40 PM

Quote:

Originally Posted by naitirps

try this:

echo "<IMG STYLE=\"position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px\" SRC=\"hair".$hair.".gif\">";

It worked beautifully. Thank you very much!

If you could explain I would cream my pants, but if you cant I am still insanely grateful. Thanks again.

octane · 02-06-2007, 07:54 PM

you can't use the same type of quotes (in this case double quotes) inside the string you're trying to print without escaping them.

basically your print statement starts at the first double quote and ends at the next one, which was right after STYLE=, and that caused the error.

woj · 02-06-2007, 08:44 PM

Quote:

Originally Posted by DjSap

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

or just escape the -> " characters

PHP-CODER-FOR-HIRE · 02-06-2007, 09:08 PM

Quote:

Originally Posted by DjSap

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

If you want to be like that, you shouldn't use single quotes in HTML attributes.

The ultimate correct way is like this:

echo '<img src="whatever.gif" class="super_pic" style="border: 1px solid red;" />';

Print is not required here, nor is escaping quotes.

02-06-2007, 07:24 PM	#1
Kard63 Confirmed User Join Date: Nov 2003 Location: 237 619 975 Posts: 8,944	embedding CSS in PHP, example, please look print "<IMG STYLE="position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px" SRC="hair$hair.gif">"; Whats wrong with that line? thanks. __________________

02-06-2007, 07:27 PM	#3
Kard63 Confirmed User Join Date: Nov 2003 Location: 237 619 975 Posts: 8,944	the line: print "<img src = hair$hair.gif>"; works. but when I try to add CSS it goes to shit. __________________

02-06-2007, 07:29 PM	#4
DjSap Confirmed User Join Date: Jul 2002 Posts: 3,869	A. You do not fucking do that, all styles go into the CSS file, no hardcoding print "<IMG class='imgstyle' SRC='hair$hair.gif'>"; __________________ Blog Themes, TGP Design, Writing Services, Grunt Work ICQ: 66871495

02-06-2007, 07:30 PM	#5
naitirps Confirmed User Join Date: May 2004 Location: ... Posts: 761	try this: echo "<IMG STYLE=\"position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px\" SRC=\"hair".$hair.".gif\">"; __________________ Programmer ICQ 44035273 \| AIM spritwork \| Email spritian at spritian dot com

02-06-2007, 07:54 PM	#7
octane Registered User Join Date: Mar 2006 Posts: 32	you can't use the same type of quotes (in this case double quotes) inside the string you're trying to print without escaping them. basically your print statement starts at the first double quote and ends at the next one, which was right after STYLE=, and that caused the error.