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Old 11-28-2005, 03:29 PM   #1
The Duck
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Math: Formal proof

Ive beem beating my head against the wall trying to make a formal proof for this problem

(p v q) -> r
(q v r) -> (~s v t)
p ^ s
.: t

I havent been able to find any good help online and im just not getting anywhere so if anyone good at logic can help me id appreciate it.
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Old 11-28-2005, 03:36 PM   #2
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College Homework Surfer. QED.
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Old 11-28-2005, 03:36 PM   #3
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ask dr.math

all logic proofs have already been proved...this shouldnt be a hard one...but not something ill spend twenty minutes on...im going home to play video games instead
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Old 11-28-2005, 03:37 PM   #4
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i hate math
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Old 11-28-2005, 03:39 PM   #5
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Quote:
Originally Posted by gornyhuy
College Homework Surfer. QED.
College homework surfer? Ok......
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Old 11-28-2005, 06:08 PM   #6
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math makes me sick.
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Old 11-28-2005, 06:21 PM   #7
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Good luck.
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Old 11-28-2005, 06:33 PM   #8
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http://www.anvari.org/fun/Gender/Pro..._are_Evil.html
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Old 11-28-2005, 10:12 PM   #9
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I don,'t think I encountered that on my college algebra.
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Old 11-28-2005, 11:43 PM   #10
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Quote:
Originally Posted by kandah
Ive beem beating my head against the wall trying to make a formal proof for this problem

(p v q) -> r
(q v r) -> (~s v t)
p ^ s
.: t

I havent been able to find any good help online and im just not getting anywhere so if anyone good at logic can help me id appreciate it.

where are the numbers?
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Old 11-28-2005, 11:43 PM   #11
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awwwwwww math
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Old 11-28-2005, 11:59 PM   #12
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sorry dude, I can't help you with that equation.
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Old 11-29-2005, 12:01 AM   #13
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(p v q) -> r equals (~s v t)[p ^ s]3

.: this is just a formula terminator so not relevant
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Old 11-29-2005, 12:26 AM   #14
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Quote:
Originally Posted by kandah
Ive beem beating my head against the wall trying to make a formal proof for this problem

(p v q) -> r
(q v r) -> (~s v t)
p ^ s
.: t

I havent been able to find any good help online and im just not getting anywhere so if anyone good at logic can help me id appreciate it.

Thats actually logic..
lets see if we can do it together..

p or q if then r on line 1. but i believe it becomes an and because its in bracktes, so p&q if then r for line 1

q or r if then it is not the case the s is x or t
p and s
therefore t.

shit man,, i forget which rule it is but you need to flip the first one around and change the cotraction to a conjunction to get the T by itself, then flip the entire second line but change the negative quantifier. then deduce and you should get your conclusion.
hope this helps
duke
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Old 11-29-2005, 12:28 AM   #15
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It's a "i hate math world."
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Old 11-29-2005, 04:13 AM   #16
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Any math wizard on this board?
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Old 11-29-2005, 04:26 AM   #17
com
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Quote:
Originally Posted by DukeSkywalker
Thats actually logic..
lets see if we can do it together..

p or q if then r on line 1. but i believe it becomes an and because its in bracktes, so p&q if then r for line 1

q or r if then it is not the case the s is x or t
p and s
therefore t.

shit man,, i forget which rule it is but you need to flip the first one around and change the cotraction to a conjunction to get the T by itself, then flip the entire second line but change the negative quantifier. then deduce and you should get your conclusion.
hope this helps
duke
i think i remember hearing something to this effect as I was on my way to sleep in class at some point... does someone want to remind me where these kinds of excercises come into play?
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Old 11-29-2005, 05:07 AM   #18
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the answer is 4.
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Old 11-29-2005, 05:08 AM   #19
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Lets see here

1. p v s 1. premise
2. p 2. simplifciation (1)
3. s 3. simplifciation (1)
4. (p v q) 4. premise
5. ~(p v q) -> r 5..Contiditional equivalence (4)
6 ~p v (q v r) 6 Associated equivalence (5)
7. q v r 7. Disjunctive syllogism (2,6)
8. (q v r) -> (~s v t) 8. Premise
9. ~s v t 9. Modus Pones (7)
10. T 10. Disjunctive syllogism (3,9)
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Old 11-29-2005, 10:27 AM   #20
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hehe! almost everyone here hates math! same with me...doesn't liked it all!
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Old 11-29-2005, 11:42 AM   #21
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