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#1 |
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Join Date: Jun 2002
Location: Medellin, Colombia
Posts: 6,445
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my friend has a physics problem..
driving along a freeway, you notice that it takes a time t to go from one mile marker to the next. When you increase your speed by 8 mi/h , the time to go one mile decreases by 10 s . What was your original speed?
how do u get this answer..
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#2 |
Confirmed User
Join Date: Mar 2003
Posts: 365
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I think it's a system problem.
v = d / t so, t = 1 (1 mile) / v and t - 10 = 1 / (v + 8) isolate a variable and solve for it... |
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#3 |
Too lazy to set a custom title
Join Date: Feb 2001
Location: Tube Titans, USA
Posts: 11,929
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v1 = first velocity
v2= second velocity d1- first distance d2 = second distance d1 = d2 = 1 Since d = v/t v1*t = v2*t2 = 1 Using: v2 = v1 +8 and t2 = t = 10 (v1 + 8)(t-10) = 1 10v1 ? 8t + 80 = 0 10v1^2 + 80v1 ? 8 = 0 Using quadratic formula with a=10, b=80, c = -8 You get v1 = ~ .09878 mph which you can verify is correct by ::: In the first mile .09878 mph means you finish in 10.12 seconds. Then in the second mile you travel at 8.09875 mph which means you finish in .12 seconds
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#4 | |
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Join Date: Nov 2002
Location: AU
Posts: 183
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#5 | |
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Join Date: Jun 2003
Location: Jesusland
Posts: 10,017
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#6 |
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Join Date: Oct 2002
Location: "evitcepsrep ruoy egnahc"
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Thank you for reminding me I suck at all math asside from accounting.
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#7 | |
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Join Date: Sep 2002
Location: South Hampton
Posts: 1,795
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#8 | |
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Join Date: Jun 2003
Location: Jesusland
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#9 |
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Join Date: Mar 2004
Posts: 304
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I knew Colin would have the answer to this!!!!
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#10 | |
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Join Date: Feb 2001
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#11 | |
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Join Date: May 2002
Location: European Union
Posts: 3,815
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I don't wanna be the ass here, but I think you mixed up seconds and hours somewhere. At the beginning he drove with 50mph (and needed 72 sec for 1mile), then he increased his speed to 58mph and therefore only needed 62 sec for a mile ![]() |
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#12 | |
Too lazy to set a custom title
Join Date: Feb 2001
Location: Tube Titans, USA
Posts: 11,929
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Haha. Oh, shit. You're right. Forgot to convert the units. ![]()
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