Php help needed. - GoFuckYourself.com

4Pics · 08-19-2003, 01:19 AM

Does someone know how you do this

I'd like to generate 10 random #'s 1 thru 100 and atleast a gap of 4 apart. None can be a duplicate of the other.

Anyone know how to do that?

Thanks

Chaldoray · 08-19-2003, 01:20 AM

Yes, Pay me

SilverTab · 08-19-2003, 01:27 AM

hmm basically you just need the rand(1,100) function and you test the result with your conditions...

BlueDesignStudios · 08-19-2003, 01:29 AM

Quote:

Originally posted by SilverTab
hmm basically you just need the rand(1,100) function and you test the result with your conditions...

sounds like a good algorithm to me

Chaldoray · 08-19-2003, 01:30 AM

srand function go read on it at php.net

SilverTab · 08-19-2003, 01:31 AM

Quote:

Originally posted by BlueDesignStudios

sounds like a good algorithm to me

I'm lazy...it's 4am

I'm assuming he knows how to do while() with conditions...etc...if not then he needs someone to do the script...not some help with it..! ;-) then I could do it...but we get back to the previous point...it's 4am... i'm tired... LOL

JDog · 08-19-2003, 01:51 AM

Quote:

Originally posted by SilverTab

I'm lazy...it's 4am

I'm assuming he knows how to do while() with conditions...etc...if not then he needs someone to do the script...not some help with it..! ;-) then I could do it...but we get back to the previous point...it's 4am... i'm tired... LOL

ah, why pay someone, this script would be so easy, worth what 10 dollars...LOL...dude, he could learn the php while() command on php.net. easy to learn..

jDoG

NiteRain · 08-19-2003, 02:16 AM

Okay this covers your requirements, gives you 10 randomly generated numbers, at least 4 digits away from any other number it previously gave you.

$uniq=array();

function four_or_more_apart($number,$array){
$keys=array_keys($array);
for ($x=0; $x<count($keys);$x++){
if ($number-4<$keys[$x] && $number+4>$keys[$x]){
return 0;
}
}
return 1;
}

while($counter<10){
$number = rand(1,100);
if (!$uniq[$number] && four_or_more_apart($number,$uniq)){
$uniq[$number]++;
print "$number\n";
$counter++;
}
}

Kind of curious what yah need it for though...

igneus · 08-19-2003, 02:45 AM

my beautiful contribution

PHP Code:


			
<?php

    for ($i = 1; $i <= 10; $i++) {

        do {

            $num = rand(1, 100);

        } while (($nums[$num] != "") ||

             ($nums[$num + 4] != "") ||

             ($nums[$num - 4] != "") ||

             ($nums[$num + 3] != "") ||

             ($nums[$num - 3] != "") ||

             ($nums[$num + 2] != "") ||

             ($nums[$num - 2] != "") ||

             ($nums[$num + 1] != "") ||

             ($nums[$num - 1] != ""));



        $nums[$num] = $num;

        echo $num . "\n";

    }

?>

4Pics · 08-19-2003, 05:03 AM

I want to rotate in random sponsor galleries. I could just hardcode certain spots to be sponsors but I figured doing it random might improve my productivity? Plus new code always helps me somewhere else and I become better at php.

I appreciate the help and when I get going i'll test it out tommorow what was posted.

Thanks

check · 08-19-2003, 05:18 AM

try ghostdriver

08-19-2003, 01:19 AM	#1
4Pics Confirmed User Industry Role: Join Date: Dec 2001 Posts: 7,952	Php help needed. Does someone know how you do this I'd like to generate 10 random #'s 1 thru 100 and atleast a gap of 4 apart. None can be a duplicate of the other. Anyone know how to do that? Thanks

08-19-2003, 01:27 AM	#3
SilverTab Confirmed User Join Date: Nov 2001 Location: MTL Posts: 5,060	hmm basically you just need the rand(1,100) function and you test the result with your conditions... __________________ mmm my sig was too big... no more cool animation but hey still! need php? ICQ: 94586959

08-19-2003, 02:16 AM	#8
NiteRain Confirmed User Join Date: Jul 2002 Location: Fort Lauderdale Posts: 600	Okay this covers your requirements, gives you 10 randomly generated numbers, at least 4 digits away from any other number it previously gave you. $uniq=array(); function four_or_more_apart($number,$array){ $keys=array_keys($array); for ($x=0; $x<count($keys);$x++){ if ($number-4<$keys[$x] && $number+4>$keys[$x]){ return 0; } } return 1; } while($counter<10){ $number = rand(1,100); if (!$uniq[$number] && four_or_more_apart($number,$uniq)){ $uniq[$number]++; print "$number\n"; $counter++; } } Kind of curious what yah need it for though... Last edited by NiteRain; 08-19-2003 at 02:34 AM..

08-19-2003, 02:45 AM	#9
igneus Registered User Join Date: Jul 2003 Posts: 77	my beautiful contribution PHP Code: <?php for ($i = 1; $i <= 10; $i++) { do { $num = rand(1, 100); } while (($nums[$num] != "") \|\| ($nums[$num + 4] != "") \|\| ($nums[$num - 4] != "") \|\| ($nums[$num + 3] != "") \|\| ($nums[$num - 3] != "") \|\| ($nums[$num + 2] != "") \|\| ($nums[$num - 2] != "") \|\| ($nums[$num + 1] != "") \|\| ($nums[$num - 1] != "")); $nums[$num] = $num; echo $num . "\n"; } ?> __________________ icq: 201430673

08-19-2003, 01:20 AM	#2
Chaldoray Confirmed User Join Date: Jul 2003 Posts: 2,868	Yes, Pay me

08-19-2003, 01:30 AM	#5
Chaldoray Confirmed User Join Date: Jul 2003 Posts: 2,868	srand function go read on it at php.net

08-19-2003, 05:03 AM	#10
4Pics Confirmed User Industry Role: Join Date: Dec 2001 Posts: 7,952	I want to rotate in random sponsor galleries. I could just hardcode certain spots to be sponsors but I figured doing it random might improve my productivity? Plus new code always helps me somewhere else and I become better at php. I appreciate the help and when I get going i'll test it out tommorow what was posted. Thanks

08-19-2003, 05:18 AM	#11
check Confirmed User Join Date: Apr 2003 Posts: 315	try ghostdriver