Javascript to alternate between two sources

[dready]

Anyone have a code handy that would allow you to alternate between two javascript sources with each page load? Right now I have:

<SCRIPT LANGUAGE="JavaScript" SRC="1.js">
</SCRIPT>

And

<SCRIPT LANGUAGE="JavaScript" SRC="2.js">
</SCRIPT>

I'd like to only load one, and make it 50/50 between 1.js and 2.js

[BestXXXPorn]

you could save the last one loaded in a cookie and then keep alternating... if you don't need to it to be absolutely perfect an easier method would be to just use a random number, 1 or 2 :P

[ProG]

You will not get a solid 50/50 split unless you keep a count for each one. Random is usually pretty close but it could easily go 60/40 or worse, or better... it's called random for a reason.

[AIbenjamink]

If you want an even 50/50 split, your best implementation would most likely be accomplished server side, using PHP etc..

[quantum-x]

You will not get a solid 50/50 split unless you keep a count for each one. Random is usually pretty close but it could easily go 60/40 or worse, or better... it's called random for a reason.

Bullshit. Go flip a coin 1,000,000 times and tell me if it goes out to 60/40.

[dready]

Would this do it?

<script type="text/javascript">
<!--
var rand = Math.floor(Math.random()*2)+1;
document.write('<script type="text/javascript" src="'+rand+'.js");</script>');
</script>

[quantum-x]

If PHP is in your reach, try:

<SCRIPT LANGUAGE="JavaScript" SRC="<?=rand(1,2)?>.js">

If not:
<script>
var oHead = document.getElementsByTagName('HEAD').item(0);
var oScript= document.createElement("script");
oScript.type = "text/javascript";
oScript.src= Math.floor ( Math.random ( ) * 2 + 1 )+".js";
oHead.appendChild( oScript);
</script>

[quantum-x]

Would this do it?

<script type="text/javascript">
<!--
var rand = Math.floor(Math.random()*2)+1;
document.write('<script type="text/javascript" src="'+rand+'.js");</script>');
</script>

Also good

[dready]

Thanks Quantum, I'll give it a shot.

[BestXXXPorn]

Bullshit. Go flip a coin 1,000,000 times and tell me if it goes out to 60/40.

It IS possible... unlikely but still possible... It also has a LOT to do with sample size :P

[ProG]

Bullshit. Go flip a coin 1,000,000 times and tell me if it goes out to 60/40.

Not sure what you are saying. I know you are smart enough to know that random will never be equal. The FACT is, if you want it to be 50/50 exactly, random isn't going to work.

Also, BestXXXPorn is correct. The sample size plays a huge role. If you have 100 hits, it could very easily go 60/40.

[quantum-x]

Not sure what you are saying. I know you are smart enough to know that random will never be equal. The FACT is, if you want it to be 50/50 exactly, random isn't going to work.

Also, BestXXXPorn is correct. The sample size plays a huge role. If you have 100 hits, it could very easily go 60/40.

It's really simple: When a coin is flipped, it is a 50% chance of being heads or tails.
Previous flips do not influence this chance.

Therefore, it WILL average out very close to 50/50 over a large sample set - that's why I said 'flip a coin 1,000,000 times'

[seeandsee]

do true unique page load, every next time different script

[ProG]

It's really simple: When a coin is flipped, it is a 50% chance of being heads or tails.
Previous flips do not influence this chance.

Therefore, it WILL average out very close to 50/50 over a large sample set - that's why I said 'flip a coin 1,000,000 times'

The OP didn't ask for an average, he asked for a 50/50 split, which you can't guarantee with random. Just because you have a 50% chance of getting heads or tales does not mean you get 50% heads and 50% tales. If you made a machine to flip coins exactly the same every time (removing the random factor) you would always get the same result not 50/50.

Not to mention if he wanted to add a 3rd option, the "averages" are much worse.