any developers code shell scripts?

[fris]

anyone code bash shell scripts?

leave your contact info

thanks.

[PowerCum]

Usually people would say "See sig"

In this case I can only say... Look at YOUR sig

[fris]

ya, they dont do shell scripting, or else i wouldnt have made the post

[PowerCum]

Search round on freshmeat and sourceforge.
Unless you need something really complex it's probably done already.

Image resizing, movies pics extraction and so on... there are like 500 scripts that do these tasks.

[fris]

Search round on freshmeat and sourceforge.
Unless you need something really complex it's probably done already.

Image resizing, movies pics extraction and so on... there are like 500 scripts that do these tasks.

need something custom, but not complex.

its for posting to a source code site from the command line.

one of the parameters is tags:

tag1,tag2,tag3

not sure how to parse that in a shell script

[nation-x]

why does it need to be a "bash" shell script? You can run perl, php, etc from the shell.

http://www.phpbuilder.com/columns/darrell20000319.php3

[mrkris]

why does it need to be a "bash" shell script? You can run perl, php, etc from the shell.

My thoughts exactly.

[nation-x]

#!/usr/local/bin/php -q
<?php
// $argc contains the count of arguments passed
echo "Total argument passed are : $argc \n";

if ($argc) {
	// $argv contains an array of the arguments that were passed
	foreach($argv as $arg) {
		echo $arg."\n";
	}
}
?>

[nation-x]

Usually people would say "See sig"

In this case I can only say... Look at YOUR sig

stfu... real webmasters are posting... not thieving bitches

[fuzebox]

Generally for command line stuff I just do it in perl.

[tranza]

#!/usr/local/bin/php -q
<?php
// $argc contains the count of arguments passed
echo "Total argument passed are : $argc \n";

if ($argc) {
	// $argv contains an array of the arguments that were passed
	foreach($argv as $arg) {
		echo $arg."\n";
	}
}
?>

Thanks for this bro! ;)

[doridori]

see see sig

[nation-x]

Thanks for this bro! ;)

np..

doridori - go eat a sick dick punk

[fris]

this basically does what i want it to do, but in perl

#!/usr/bin/perl -w

use strict;
use Frontier::Client;

my $apikey = 'APIKEYHERE';	
my $src = 'sourcecode.phps'; 
my $title='test post';
my $code = '';
my $tags = 'tag1 tag2 tag3';
my $language = 'php';
my $flag = 0;

open(FC, "<:utf8", $src);
while (<FC>) {
	if (/^\#[^!]\s*(.+)/ && $flag == 0) {
		$title = $1;
		$flag++;
	}
	elsif (/^\#[^!]\s*(.+)/ && $flag == 1) {
		$tags = $1;
		$flag++;
		if (/(\w+) (.+)/) {
			$language = $1;
			$tags = $2;
		}
	}
	$code = $code . $_;
}

my $session = Frontier::Client->new( url => 'http://snipplr.com/xml-rpc.php', debug => 0,);
my @args = ($apikey, $title, $code, $tags, $language);
my $result = $session->call('snippet.post', @args);

the command line version of it using the snipplr ruby gem would be

snipplr -c -meta ":title=>'test post',:tags=>'tag1 tag2 tag3',:language=> 'php'" < sourcode.phps

[k0nr4d]

It sounds to me like the 'curl' command line does exactly what you are after...
http://curl.haxx.se/docs/manpage.html

...or i might have misread completely.

[nation-x]

hehe... today is the first time I ever looked at snipplr... how funny