embedding CSS in PHP, example, please look

[Kard63]

print "<IMG STYLE="position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px" SRC="hair$hair.gif">";



Whats wrong with that line? thanks.

[Chio]

print "<IMG STYLE="position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px" SRC="hair$hair.gif">";



Whats wrong with that line? thanks.

I'm not a coder at all but maybe you need to escape out some of those characters?

[Kard63]

the line:

print "<img src = hair$hair.gif>";

works. but when I try to add CSS it goes to shit.

[DjSap]

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

[naitirps]

try this:

echo "<IMG STYLE=\"position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px\" SRC=\"hair".$hair.".gif\">";

[Kard63]

try this:

echo "<IMG STYLE=\"position:absolute; TOP:35px; LEFT:170px; WIDTH:50px; HEIGHT:50px\" SRC=\"hair".$hair.".gif\">";

It worked beautifully. Thank you very much!

If you could explain I would cream my pants, but if you cant I am still insanely grateful. Thanks again.

[octane]

you can't use the same type of quotes (in this case double quotes) inside the string you're trying to print without escaping them.

basically your print statement starts at the first double quote and ends at the next one, which was right after STYLE=, and that caused the error.

[woj]

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

or just escape the -> " characters

[PHP-CODER-FOR-HIRE]

A. You do not fucking do that, all styles go into the CSS file, no hardcoding

print "<IMG class='imgstyle' SRC='hair$hair.gif'>";

If you want to be like that, you shouldn't use single quotes in HTML attributes.

The ultimate correct way is like this:

echo '<img src="whatever.gif" class="super_pic" style="border: 1px solid red;" />';


Print is not required here, nor is escaping quotes.