Math problem... solving for a variable thats an exponent

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  • Myst
    Confirmed User
    • Feb 2004
    • 4708

    #1

    Math problem... solving for a variable thats an exponent

    Umm so Im taking an actuarial science course for the spring
    I cant for the life of me remember how to do this cause its been so long

    how do you solve
    1.08^-n + 1.08^-2n = 1
    ICQ: 298-523-037
  • fallenmuffin
    Confirmed User
    • Nov 2005
    • 8170

    #2
    irc://irc.efnet.net/math

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    • gooddomains
      Too lazy to set a custom title
      • Jul 2003
      • 10127

      #3
      1+1=3 :-)

      Comment

      • deef-thp
        Confirmed User
        • Sep 2005
        • 371

        #4
        -48.830373630755
        ICQ: 6437580

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        • AmigoPorn
          Too lazy to set a custom title
          • Jul 2003
          • 21583

          #5
          1.08^-n + 1.08^-2n = 1

          1 + 1.08^-n = 1 ( 1.08^n )

          -1.08^n + 1.08^-n + 1 = 0

          -1.08^n + 1 / ( 1.08^n ) + 1 = 0

          -1.08^2n + 2 = 0

          1.08^2n = 2

          2n = log 2 / log 1.08

          2n = 9.006468342

          n = 4.503234171
          ICQ: 267899523


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          • dave_w
            Confirmed User
            • Dec 2005
            • 247

            #6
            Originally posted by AmigoPorn
            1.08^-n + 1.08^-2n = 1

            1 + 1.08^-n = 1 ( 1.08^n )

            -1.08^n + 1.08^-n + 1 = 0

            -1.08^n + 1 / ( 1.08^n ) + 1 = 0

            -1.08^2n + 2 = 0

            1.08^2n = 2

            2n = log 2 / log 1.08

            2n = 9.006468342

            n = 4.503234171


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