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		#1 | 
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				php question
			 
			I am new to php and am working on a script to show search results. I am getting the following error with this and was wondering if I am doing something wrong or have the wrong version of php on my server because I am copying this code directly from php5 and mysql4 for dummies and have php4 on my server: 
		
	
		
		
		
		
		
	
	<?php $user = "user"; $host = "localhost"; $password = "pass"; $database = "database"; $connection = mysql_connect($host,$user,$password) or die ("Couldn't connect to server"); $db = mysql_select_db($database,$connection) or die ("Couldn't select database"); $query = "SELECT * FROM `features`"; $result = mysql_query($query) or die ("Couldn't execute query."); /* Dsiplay results in a table */ echo "<table cellspacing='10' border=0' cellpadding='0' width='100%'?"; echo "<tr><td colspan='5' align='right'>Click on any picture to see a larger version.<br><hr></td></tr>\n; while ($row = mysql_fetch_array{result,MYSQL_ASSOC)) { /* display row for each listingid */ echo "<tr>\n; echo "<td>{$row['intersection1']}</td>\n"; ?> I get his error: Parse error: parse error, unexpected '>' in /public_html/pa/index.php on line 26  | 
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		#2 | 
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		 you need a " at the end of your echo 
		
	
		
		
		
		
		
	
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		#3 | 
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		 twice 
		
	
		
		
		
		
		
	
	...  | 
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		#4 | 
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			 <&(©¿©)&> 
			
		
			
				
			
			
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		 change this: 
		
	
		
		
		
		
			echo "<tr><td colspan='5' align='right'>Click on any picture to see a larger version.<br><hr></td></tr>\n; to: echo "<tr><td colspan='5' align='right'>Click on any picture to see a larger version.<br><hr></td></tr>\n"; in case it wasn't obvious what arnette said... 
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		#5 | |
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		 Quote: 
	
 echo "<tr>\n; to: echo "<tr>\n";  | 
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		#6 | 
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			 Damn Right I Kiss Ass! 
			
		
			
			
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		 No you didn't close the loop with a } 
		
	
		
		
		
		
		
	
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		#7 | 
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			 Damn Right I Kiss Ass! 
			
		
			
			
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		 Also, this is better written from, 
		
	
		
		
		
		
		
	
	Code: 
	echo "<td>{$row['intersection1']}</td>\n";
Code: 
	echo "<td>".$row['intersection1']."</td>\n";  | 
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		#8 | |
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		 Quote: 
	
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		#9 | 
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		 Still shows same error after changing to: 
		
	
		
		
		
		
		
	
	/* display row for each listingid */ echo "<tr>\n"; echo "<td>{$row['intersection1']}</td>\n"; ?>  | 
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		#10 | |
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		 Quote: 
	
 put a } before the ?>  | 
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		#11 | 
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		 also 
		
	
		
		
		
		
		
	
	while ($row = mysql_fetch_array{result,MYSQL_ASSOC)) is wrong, it should be while ($row = mysql_fetch_array($result,MYSQL_ASSOC))  | 
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		#12 | 
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		 Ok changed to: 
		
	
		
		
		
		
		
	
	Code: 
	/* Dsiplay results in a table */
echo "<table cellspacing='10' border=0' cellpadding='0' width='100%'?";
echo "<tr><td colspan='5' align='right'>Click on any picture to see a larger version.<br><hr></td></tr>\n";
while ($row = mysql_fetch_array{result,MYSQL_ASSOC))
/* display row for each listingid */
echo "<tr>\n";
echo "<td>".$row['intersection1']."</td>\n";
?>
Parse error: parse error, unexpected '{' in /public_html/pa/index.php on line 22  | 
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		#13 | 
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		 you didnt copy this code very well... 
		
	
		
		
		
		
		
	
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		#14 | |
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		 Quote: 
	
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		#15 | 
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		 Code: 
	echo "<table cellspacing='10' border=0' cellpadding='0' width='100%'?"; also the "?" at the end of it should be a ">" instead e.g: Code: 
	echo "<table cellspacing='10' border='0' cellpadding='0' width='100%'>";  | 
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		#16 | 
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			 Damn Right I Kiss Ass! 
			
		
			
			
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		 Did you END the loop? 
		
	
		
		
		
		
		
	
	Code: 
	while ($row = mysql_fetch_array{result,MYSQL_ASSOC))
{
/* display row for each listingid */
echo "<tr>\n;
echo "<td>{$row['intersection1']}</td>\n";
}
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		#17 | 
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			 Confirmed User 
			
		
			
				
			
			
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		 man your screwing it all up ... now you need a { after your while statement 
		
	
		
		
		
		
		
	
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		#18 | |
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		 Quote: 
	
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		#19 | 
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		 wow you guys are fast posters  
		
	
		
		
		
		
			
		
		
		
		
	
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		#20 | |
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		 Quote: 
	
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		#21 | 
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		 Added the loop, Even better, Thanks! 
		
	
		
		
		
		
		
	
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		#22 | 
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			 Damn Right I Kiss Ass! 
			
		
			
			
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		 Not to mention, mysql_assoc_array($result) 
		
	
		
		
		
		
		
	
	would work for that section too.  | 
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		#23 | |
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			 Damn Right I Kiss Ass! 
			
		
			
			
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		 Quote: 
	
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		#24 | 
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		 One more quicky, how do I make it display Intersection1 & Intersection2 such as "Street1 & Street2" in the line : 
		
	
		
		
		
		
		
	
	echo "<td>".$row['intersection1']."</td>\n";  | 
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		#25 | ||
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		 Quote: 
	
 Quote: 
	
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		#26 | |
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		 Quote: 
	
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		#27 | 
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		 Thanks again! 
		
	
		
		
		
		
		
	
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		#28 | 
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		 Didnt know ya were into PHP V! 
		
	
		
		
		
		
			Nice 
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