Where's a good place to sell a domain?
 

Title says it all...

It's just been sitting on Sedo for awhile now and not much interest. So where's a good place to get a quick sell?

Buy & Sell forum

whats the domain?

theres always here...and sedo

It depends on what its worth. The buy and sell at most forums is over capacity with sellers, and the average price is under $100. From what I have seen, very few buyers that post a reasonable budget.
And to make matters worse everytime someone post "looking for a 3 char .com for under $100", some idiot who needs beer money sells him one.
If your looking to get high $xxxx for it, I would go with a service were you will get a good price.

Under $300 you can sell anywhere.

sedo of course

Here?....

I've got some great domains from the buy and sell forum here recently - but it's definately a buyers market

A lot depends on the name itself. If it's crap you'll never sell it anywhere - if it's good you can sell it anyplace.

It's a mainstream domain or adult domain depending on how you look at it. I offered it here and there was some interest but nothing major. So I want to hit the mainstream market. It's not that great of domain just trying to get something for it. It's an okay 5 letter cams domain.

5 letter cam domain? madawgz the domain appriaser would value that at $200,000 - $250,000

GFY.com, of course :)

Forgot about the 's' ... lol 6 letters. Damn that dropped it down to $10,000 didn't it? lol

As has already been mentioned - sedo is probably your best bet or you could try afternic , ( although not as popular as sedo ).

Another option would be to hawk it round the mainstream affiliate forums but IMHO you should do better with it on the auction sites *if* it's any good.

One final word of advice is to be patient with selling it. If it doesn't meet your reserve first time round wait a while and then put it in again. I've seen loads of names sell for $50 - $100 when in fact they are probably worth 10x that but their owners didn't realise, ( or were conned ), out of there true value.