Can someone help me with cron job formatting?
 

I am trying to get this Cron Job to work, and I thought I had it and it ended up spitting out this error

GET: not found

here is the job:

is something wrong in that?

this is a phpbb mod that publishes RSS feeds as topics in the forum

Link to MOD?

I might be wrong on this one, but why not just simply

/usr/local/bin/php (or depending on your echo `which php`

absolutepathofyourphp/members/forum/mods/netclectic/find_input/includes/news_insert.php 2> /dev/null

If its local.
Otherwise wget it?

'you lost me...i am not the most linux proficient

100646962 contact me :)

erm GET ?
try fetch or wget instead of GET

u lamer

shit, here is the mod, that other link is wrong

http://www.phpbb.com/phpBB/viewtopic.php?t=42364

use wget better,
seems like you don't have the GET tool on your server.

first off how often does it need to run, to run every minute (assuming the script is on your local server you would put:
*/1 * * * /your/path/to/php /full/path/to/members/forum/mods/netclectic/find_input/includes/news_insert.php >/dev/null 2>&1


Otherwise, if it's on a foreign server, which wouldn't make sence make /your/path/to/php /your/path/to/curl or lynx

It looks bad ass

> Does it make a RSS feed?
No, although there is a companion mod which does. See [BETA] FIND - Forum Integrated News Delivery - Output

> or is it to put an RSS feed onto a forum page?
Yes, kind of. It doesn't just display the feed on your page, it enters the contents as topics in your forums.