Science question.
 

How big can a rock be before it is to large and collapses in on itself?

Who gives a fuck :)

tree fiddy.

Earth is a rock.

Ok so it would need to be larger than earth, but how large?

you talking about the sun........

larger than jupiter

if the sun collapses we will all be sucked in to it.

The sun is not a rock.

Any piece of matter over 12.6 million miles in circumference will begin to collapse onto itself and has the potential to become a "black hole". We're talking fucking HUUUGGEEEEEE.....

:2 cents:

-P






PS: i just made that shit up.

I guess BIG :thumbsup

Jupiter is also not a rock.

Depends on the mass of the rock. You could have a 1 inch radius peice of matter that collapses on itself, you could have an infinitely large peice of matter that did not...

Just caught your PS. Cause I was about to say Earth has a circumference of 24902 miles.

Wouldn't that form a blackhole or something like that ?

I do not think so.
There just has to be a point that a rock would reach in size that eventually it was just to big and the internal pressures could no longer hold its size and would thus just liquefy the entire thing or turn gaseous.

Actually we wouldnt. For a star to be transformed into a blackhole it first has to go SuperNova. The star itself has to be MASSIVE, like 8 times the mass of our sun.

jupiter isn't rock of any type. it is a gas giant. the only planets in our solar system that are comprised mainly of rock are the inner planets.

mercury
venus
earth
mars

possibly pluto, but they are not sure yet. pluto is most likely just a large chunk of ice and debris from the kyper belt.

what colour is the train?

Come on I was pondering this for a good hour last night while I was waiting to fall asleep.

Ok, I was goofing in my last post, but on a more serious note ...

What KIND of rock? Granite certainly has a different density than, say, limestone and therefore the size necessary for a "collapse" would be different.

-P

Well when I was going over it, I was just thinking a rock style planet. Naturally Earth itself is an assortment of all the rocks, and I would presume a larger rock planet would also be the same (crossing out marble and other compressed bone rocks of course).

Didn't you learn physics in the shcool??? The answer to your question depends on rock's material (I mean the parameters liks solidity, soundness and friability) And also it depend's on its shape and position relatively to the bearing(s). In complex cases you may even draw a load diagram :winkwink:

P.S. The US educating system sux again...

No I did not learn physics in shcool, I was taught them in school.
This is a hypothetical question of course. One that would depend on geology as well as physics. I have no clue as to what pressures cause one rock to be pressed into another and so on. So alas I was thinking along the lines of a rock type planet. There has to be a maximum size one could be before it could not support its own weight.

Density. Period. Theoretically, any mass -- if compressed to small enough space -- can become a black hole. On the flipside, if you release all the energy in a grain of salt, it would boil an olympic-size swimming pool for several hours -- :)

http://www.matter-antimatter.com/supernova1.gif



2hp

Ok I had a thought ... I think you're looking at this wrong.

As the planet gets bigger ... ie more "rock matter" is added to it, its gravity will increase. As the gravity increases it will continue to become more dense (and possibly smaller in "size"?), although its' increased gravity will also cause more matter to be pulled to it, and the cycle continues. Would the planet actually continue to get "bigger" in "size" though? Or would it's density simply increase at an alarming rate until it becomes a black hole? Or would it reach a "size" where it would become unstable for some reason... perhaps if it wasn't dense enough?

Lol

<-Not quitting my day job.

-P

Also depends on the rock's material. If you know it, you know:
1) it's strength (an ability to resist pressure)
2) it's density

the planet's gravitation depends on its size (diameter) and the rock's material (if that hypothetical planet is homogeneous). so you may see the point when the force of planet's gravitaion F (m*g) is greater than rock's strength.

where: m is a mass of the planet (depends on rock's density and planet's size (volume)) and g is a gravitational acceleration constant.

That's absolutely correct! But After Shock Media asked about the point when the rock's structure will be destroyed by it's own mass (i.e. BEFORE if will be compressed into the more dense rock) :winkwink:

quark stars are really small

Stars no matter the type do not fall under the rocky planet categories.

Translation, stars never are rocks.

Wouldn't the pressure eventually just cause so much heat it would liquify the rock itself by turning it molten or gaseous though?

Preasure (I mean just the force without compression movement of rock) CAN NOT cause any heat at all. I.e. first of all your rock have to lose its structure (must be crushed by itself) to be moved. Only after that the pressure could cause the heat. I.e. the compression process should begin.

P.S. I'm not so sure for the tech definitions above because English is not my motherlanguage as you may note already :winkwink:

You sure?

P.S. Only compression (volume reduction) causes a heat, as well as the expansion (volume enlargement) causes a cold. But not the preasure (force) itself!

This is something that you should learn when you were a schoolboy.

Yep, 100% sure. I've done a Russian high school about 15 years ago, but I still remember the basics of physics :winkwink:

I did not get a great deal of sleep so maybe I am not explaining it properly.

Basicly wish to know what is the maximum size a rock category planet could be.
There has to be some limit or basic answer without knowing every variable.

as big as my cock

i sale short rocks.

There is no single answer to your question. Because such a limit depends on 2 variables:
1) rock's density (aka breaking point)
2) rock's strength/durability

I.e. the the limin is a function of these 2 variables:
limit = f(p, t)

where:
- t is breaking point;
- p is density

Do you understand this?

Third Rock from m' baaalllssss....

No there is not an answer (known) to this.

1.) To make the correct determination, you HAVE to know all of the variables.

2.) Until proven otherwise, there is NOT a maximum size.

Questions like this are the reasons why I hate Physics.. :(

I'm pretty sure this is the right answer.

Any kind of mass can implode if the right conditions occur.

I'm also pretty sure that stars are the only things we know of that implode under thir own weight like this.

Roosters don't lay eggs.

http://www.eclipse.net/~cmmiller/BH/bhqa.html#khansonq

This page should explain some aspects of it.