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HELP PLZ (hard math problem)
I need a problem solved. Plz help.
Find constants a,b,c, and d such that the graph of the function: f(x)=ax^3+bx^2+cx+d has a local extreme at (0.3) and a point of inflection at (1,-1). If any one can answer this then A MILLION THANK YOU'S If no one can; then can you give me some links where I can ask to get a quick answer. PLEASE |
the answer is b to the power of 4
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The asnswer is R3K.
I had that same problem last year. |
Paycheck + Nice car & House = Mad Ho's
Only equation i know http://bbs.gofuckyourself.net/board/wink.gif ------------------ -- Digital Pimp Family -- |
... have your tried http://www.f(x)=ax^3+bx^2+cx+d.com ????
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You must be shitting me !
We're here to make money, not math problems ! |
whats is x stands for ?
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Thanx for the "creative" replies but I have a major test tommorrow and I need to know how to do this cause its gonna be 30% of the mark.
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Damn, that brings back memories. I rember doing functions in college, but can't remeber how to do them now. If you have AOL, there's a forum there where you can get an answer.
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Geez, i gave you the answer, what more you want? Trust me, its right, go in tomorrow, mark that as the answer and get your 30%
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Give me a fucking break....pick up the damn book, pay attention in class and stop pretending to be a webmaster. http://bbs.gofuckyourself.net/board/rolleyes.gif
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Gary is just fucking with you the real answer is R3K!!
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Oh, and in case anyone thinks I'm being too hard on the kid, the answer is here: http://www.geocities.com/CapeCanaver...26/page23.html
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I owe you one |
Spoke to soon.
That page still doesn't help http://bbs.gofuckyourself.net/board/frown.gif Thanx for trying. |
b to the power of 4!
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The kids gonna flunk anyway. That problem isn't about the answer, it's about how to draw graphs with descriptions.
The idea is that they describe the points of interest, where the graph changes direction and where it's centered and you draw it. |
i chekced the that geocities website but i did not understand anything... But i guess this one is true too.
Take the deriviative of the equation and then set it to zero. And then take the second deriviative of the equation and set it to 1. And take the third deriviative and set it -1. This way you will have 3 equations and simply solve all oof them and then you will get the answers... ------------------ slutcash- High quality free content, bannerless free hosting, pays ontime everytime and exclusive banners!!! |
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I used to be good at this, but now I don't now how to get the right resolt!
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does this class suppose to help you make alot of money?
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f(x)=ax^3+bx^2+cx+d
f'(x)=3ax^2+2bx+c f''(x)=6ax+2 Local Extreme (0/3): 0 = 3ax^2 + 2bx + c 0 = c POI ( 1/-1): 0 = 6ax + 2 -1 = 6a + 2 -3 = 6a a = -0.5 P(0/3): 3 = ax^3+bx^2+cx+d 3 = d Now, insert all variables to get b using the POI: -1=ax^3+bx^2+cx+d -1 = -0.5x^3 + bx^2 + 3 x = 1 -1 = -0.5 + b + 3 -3.5 = b Complete graph: f(x) = -0.5x^3 - 3.5x^2 + 3 Just trying to see if this is correct: f'(x) = -1.5x^2 - 7x 0 = -1.5x^2 - 7x 0 = x*(-1.5x -7) x1 = 0 correct x2 = 4.6 Oh, this is fun http://bbs.gofuckyourself.net/board/smile.gif ------------------ Current Special: TGP POSTER SPECIAL. [email protected] ICQ: 17021242 Need a host? |
you ought to buy a ti-89. those things can do all calculus.
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There's an error somewhere but I'm too tired to look for it http://bbs.gofuckyourself.net/board/smile.gif Maybe someone else can find it hehe.
It's been a long time since I did this at school http://bbs.gofuckyourself.net/board/smile.gif ------------------ Current Special: TGP POSTER SPECIAL. [email protected] ICQ: 17021242 Need a host? |
Coke, I'm impressed...heh heh I was way too lazy to give it that much thought, but you are mostly right.
You forgot to take the other zeroes into account. [This message has been edited by jimmy3way (edited 11-25-2001).] |
Thanx a lot everyone!
Keep the answers coming. And the stupid comments http://bbs.gofuckyourself.net/board/smile.gif |
b to the power of 4
Duh ------------------ Signup for 10 cent clicks 60% recurring, 5% referals, promote celebrities |
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I know you are never wrong. |
1)take the first deriviative
3ax^2+2bx+c=0 You will need to plug .3 to the equation. .27a+.6b+c=0 (first equation) 2)Then take the second deriviative. 6ax+2b=0 Plug -1 for this. -6a+2b=0 (second equation) 3)plug the 1 to the second deriviative 6a+2b=0 Then you should be able to grab the answers out of three equations... |
Oops, I missed the b right at the beginning, so it became a little too easy http://bbs.gofuckyourself.net/board/smile.gif
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Close but still no answer.
Keep'em coming |
The answer:
f(x)=ax^3+bx^2+cx+d ax^5+cx+d ax^5+e (0.7+c=xxx Your answer is XXX ------------------ Nude Central 60% Partnership Also Earn 10% on referrals Nude Central |
I have a tough problem to coming up, that's 50% of my grade on my exam. If anyone can help me out, I'd appreciate it.
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Hey Slick, they dont really have goats way up where you live do they? I figured you guys counted pounds of whale blubber up there http://bbs.gofuckyourself.net/board/smile.gif
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hey Za Ha,
if the extreme is at (0.3), i believe it will have infinite number of results and i can find you one that will satisfy the conditions. if you have mistyped and it was (0,3) instead, then it will have only one result, that i can find it too. let me know |
hmmm.....i'm still trying to figure it out your math promblem.
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Thanx everyone but you were all wrong http://bbs.gofuckyourself.net/board/frown.gif
The correct answer is as follows: y'=0 and therefore c=0 then you plug in (0,3) into your y and get d=3 Then you take y" and you get a=2b/6 and you find out what a is then you plug it back in and get your b. I didnt figure that out yet cause I just wanted to post a reply. Thanks for everyone that helped me get to this. And have a nice day. |
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i just asked you if you had mistyped (0,3) as (0.3) , and now you proved it http://bbs.gofuckyourself.net/board/biggrin.gif read my previous post http://bbs.gofuckyourself.net/board/smile.gif |
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j/k http://bbs.gofuckyourself.net/board/tongue.gif |
You're all a bunch of nerds http://bbs.gofuckyourself.net/board/biggrin.gif
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I don't want you adjusting any fuggin' aircraft engines. Typo...sheeit. |
Za Ha -- the answer is simple. Just sign up under me for thugcash, and we'll have the thugcash collection crew stop by your instructor's home.
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