Answer me this...
 

How come if I drop 2 objects that are exactly the sime size and shape but that have different weights, they will touch the floor at the same time?

Nobody could give me a clear answer. Please explain the physics of this to me, in a simple manner.

For those of you who are sceptical, try it.

Drop 1 full bottle of water and 1 empty bottle of water from the same height... they will hit the ground at the same time.

back to school or finish it.

because everything falls at the speed of gravity at 9.81m/s^2. Unless the item is air resisant such as a feather. Read here
http://www.glenbrook.k12.il.us/gbssc...aws/u2l3e.html

I know, I know.
Cuz the force of acceleration is the same.

But this experience only probably works at low altitudes because air resistence does not play it's part right.

yes and what you said about air resistance makes sense

Gravity

Excellent explanation

:Graucho

http://www.glenbrook.k12.il.us/gbssc...tlaws/efff.gif

Weight doesnt matter in the speed of an object falling its all in gravity pulling everything to the earth equally. Just dont stand under it ....... weight and inertia take over and thats the bitch.

Weight doesnt matter in the speed of an object falling its all in gravity pulling everything to the earth equally. Just dont stand under it ....... weight and inertia take over and thats the bitch.

thats the right answer :thumbsup

if you dropped them at lets say 20 meters...then the bottle with water would for sure hit the ground first

As has been said before, this is true at lower drop heights but because of air-resistance, this observation will not hold true with a larger drop distance within our atmosphere.

In a vacuum within earth's gravity, a feather and a brick will fall at exactly the same rate, for miles.

-P

Wow, free physics lesson in here!