Is there a fixed formula
 

...for calculating the bandwidth usage for a 500K one minute wmv or does it depend or several different factors?

Yep it is:

bandwidth usage =500K*WMV^¢+134£-41§

:Graucho :Graucho

Am I missing something? It would all depend on the number of downloads. Simple as that.

believe me ... the weather plays a key factor.

I am of course referring to a single download. I can multiple by the number of downloads.

is that weather they hit the play button ot the Save Target As button?:helpme

The weather factor I was already aware of.

Does the weather make any Diff. if there are?

high clouds
middle clouds
low clouds
fog
multi-level clouds

this weather has me confused.:winkwink:

Yeah, an easy forumula. How big is the file? Multiply by one.

tssssssss:thumbsup

Well then you have the answer to your question. Unless you mean CPU or something.

So you are saying that a 500K one minute wmv uses 500K of bandwidth. That does not sound right to me, but maybe it is.

The length of the file makes no difference man. If the file size is 500k, then that's how much bandwidth it will consume with one download. So yes.

Well I will accept that I guess. It just seemed to me that if you are down loading at say 56K per second, 10 seconds would amount to 560K, so a 60 second download at 56K should be more than a down load of 560K. You are stating that it is the size of file period. Okie Dokie.

Don't confuse the bitrate of the file with its size.