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Maths question for you all...!
The avg. (arithmetic - mean) of a and b is ninety; the avg. (arithmetic mean) of a and c is 150; what is the total value of (b-c)/2?
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Three fiddy.
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quick bitches!
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-60
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You can't solve something like this you have one equation with two unknowns. Because arithmetic average of a and b is ((a+b)/2) and you said it's 90, but you don't know from this, what is a or b
And the same is is valid for c and d, of course. |
there is no D.... unless he is seeking the sum of D as to which I thought would be X
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Macs suck!
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Math makes my brain hurt
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you just subtract 2nd equation from the first... :2 cents:
(a+b)/2=90 (a+c)/2=150 ------------------- ((a+b)-(a+c))/2=90-150 (a+b-a-c))/2=-60 (b-c)/2=-60 |
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it's whatever the rothchilds and rockefellars say it is!
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a+b=180 a+c=300 a=180-b a=300-c 180-b=300-c -b=120-c b=c-120 (b-c)/2 (c-120-c) /2 -60 |
(a+b)/2=90
(a+c)/2=150 a+b=180 a+c=300 a=180-b c+180-b=300 c-b=120 -120=b-c -60=(b-c)/2 |
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And.... wait for it.... wait for it... most of us ARE simple. lmao |
Reading this thread I see why so many people ask to explain what is the ratio column in our affiliate report and how it is calculated.
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(a+b)/2=90; (a+c)/2=150
(a+b)/2=((a+c)/2)-60 a/2 + b/2=a/2 + c/2 -60 b/2=c/2 -60 b/2-c/2=c/2-c/2-60 (b-c)/2=-60 |
tube sites
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at least 5 different methods
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22.5
Fucked if I remember how I came to it... |
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Years and years ago there was a software you could feed the two starting equations to and it would do all the steps and writing it out for you. I think it ran on my Apple ][ (yes, showing my age) - anybody remember what it was called?
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