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-   -   FINITE people HELP me out pleaz! (https://gfy.com/showthread.php?t=108905)

stanton 02-17-2003 02:33 AM

FINITE people HELP me out pleaz!
 
How many 3-digit natural numbers have no 5's but at least one 6 ?

BigFrog 02-17-2003 02:37 AM

72 i believe

Zebra 02-17-2003 02:37 AM

You trying to blow people's minds with that kinda question?

Where's Colin when you need him? I bet he has some formula memorized to figure that question out.

stanton 02-17-2003 02:39 AM

no not 72

i have a paper with answers

but they are in different order and there is no 72 on it :(

stanton 02-17-2003 02:39 AM

this is simple factorials..but i dont fucking understand it lol

OneHungLo 02-17-2003 02:40 AM

24,735

stanton 02-17-2003 02:41 AM

Quote:

Originally posted by OneHungLo
24,735
wrooong! :(

BigFrog 02-17-2003 02:44 AM

well, the way i see it....

106
116
126
136
146
166
176
186
196

206
216
226
236
246
266
276
286
296

306
316
326
336
346
366
376
386
396

406
416
426
436
446
466
476
486
496

606
616
626
636
646
666
676
686
696

706
716
726
736
746
766
776
786
796

806
816
826
836
846
866
876
886
896

906
916
926
936
946
966
976
986
996

add em up

BigFrog 02-17-2003 02:45 AM

ahh
lol, i see where i messed up already

BigFrog 02-17-2003 02:46 AM

153?

stanton 02-17-2003 02:47 AM

damn

stanton 02-17-2003 02:47 AM

you can not do cases like that

BigFrog 02-17-2003 02:47 AM

dammnit
144

stanton 02-17-2003 02:48 AM

it will take fu*ing hundreds of those

BigFrog 02-17-2003 02:48 AM

Quote:

Originally posted by stanton
you can not do cases like that
??

stanton 02-17-2003 02:49 AM

106 also can be 160 601 610 and so on for each of those.....
116
126
136
146
166
176
186
196

Pornwolf 02-17-2003 02:49 AM

Is this some kinda code question for the special people?

BigFrog 02-17-2003 02:49 AM

dammnit, im too fucking tired for this.....one more try.

stanton 02-17-2003 02:50 AM

ahhaah special people :glugglug

BigFrog 02-17-2003 02:51 AM

234 is my final answer

stanton 02-17-2003 02:52 AM

it is either 220 or 200 lol

but i can not figure it out..

SpaceAce 02-17-2003 02:53 AM

Quote:

Originally posted by stanton
106 also can be 160 601 610 and so on for each of those.....
116
126
136
146
166
176
186
196

It seems that you're missing the obvious instances of
160
161
162
163
164
166
167
168
169

260
261
262
etc...

SpaceAce

BigFrog 02-17-2003 02:58 AM

100 through 200 there are 17 instances.
200 through 300 there are 17 instances.
300 through 400 there are 17 instances.
400 through 499 there are 17 instances.
600 through 700 there are 81 instances.
700 through 800 there are 17 instances.
800 through 900 there are 17 instances.
900 through 999 there are 17 instances.

200 is right

final answer be dammned!!!

stanton 02-17-2003 02:58 AM

thanks man!!! :)

stanton 02-17-2003 03:00 AM

how about this one:

How many natural numbers less than 100000 have at least one digit repeated?

BigFrog 02-17-2003 03:00 AM

np
:sleep

stanton 02-17-2003 03:01 AM

:GFYBand

BigFrog 02-17-2003 03:02 AM

Quote:

Originally posted by stanton
how about this one:

How many natural numbers less than 100000 have at least one digit repeated?

oh lord, i think my brain is saying no to this one :ugone2far

stanton 02-17-2003 03:03 AM

:1orglaugh

stanton 02-17-2003 03:39 AM

anyone else? :hi

Filter 02-17-2003 07:52 AM

67510, sorry had too much free time I guess, the mirc script below will save you time though, even if it does take close to a minute. :glugglug

alias weird.thing {
set %repeats 0
set %start.from 0
while (%start.from <= 100000) {
echo -a progress %start.from
if ($count(%start.from,0) >= 2) { inc %repeats | goto end }
if ($count(%start.from,1) >= 2) { inc %repeats | goto end }
if ($count(%start.from,2) >= 2) { inc %repeats | goto end }
if ($count(%start.from,3) >= 2) { inc %repeats | goto end }
if ($count(%start.from,4) >= 2) { inc %repeats | goto end }
if ($count(%start.from,5) >= 2) { inc %repeats | goto end }
if ($count(%start.from,6) >= 2) { inc %repeats | goto end }
if ($count(%start.from,7) >= 2) { inc %repeats | goto end }
if ($count(%start.from,8) >= 2) { inc %repeats | goto end }
if ($count(%start.from,9) >= 2) { inc %repeats | goto end }
:end
inc %start.from
}
}


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