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-25/27 * 0.6 + 8/9 So what's the result? Isn't it 0.3(3)? Isn't 0.3(3) = 1/3 or isn't 0.6 = 3/5? :) Feel free to ask more questions if you don't understand something. :winkwink: |
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Put this in instacalc: -25/(27*(5/3)) + 8/9 I forgot the additional brackets but this is correct. -25 ----- <----- this fraction is not the same as this: 27x -25 ---- x 27 :thumbsup |
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-25/27x or (-25/27)x ? both options are very simple .. |
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-25 ---- x 27 and IS NOT equal to this -25 ----- 27x As I suggested above, just use http://instacalc.com/ to understand how exactly the following formula should be calculated: -25/27x E.g. -25/27*54 = 50 but NOT -0.01714677641. Please don't tell me I'm wrong, just copy-paste the formula into the calculator here: http://instacalc.com/ |
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I will concede that we are both correct and that the problem lies in the syntax of the formula.
I was reading -25/27x as meaning a fraction where 27x was the denominator. ie: ((-1)(25))/((27)(x)) You read it as just an order of operations: (-1)(25)/(27)(x) We are therefore both correct based on our own assumptions about the problem. |
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(-25)/ (27x) = -25/ 27 . 1/x = -25/27x (-25/27) . x = -25/27 . x/1 = -25x/27 :winkwink: |
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Syntax Error :upsidedow |
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-25 ---- x 27 Otherwise it would be written as follows: -25/(27x). It's a main rule of brackets calculation. BTW, that's how ALL the programming languages do process such a formula. -25/27x is always -25 / 27 * x but never -25 / (27 * x)! E.g.: /* PHP */ $x = 50; echo -25 / 27 * $x; or /* ANSI/ISO C */ x = 50; printf("%d\n", -25 / 27 * x); or (* ANSI Pascal *) x := 50; writeln(-25 / 27 * x); and so on... |
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-25/27x + 8/9 = 1/3 is a same as (-25/27) * x + 8/9 = 1/3 and it is a same as -25 / 27 * x + 8/9 = 1/3 and of course it's not [-25 / (27x)] + 8/9 = 1/3 |
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x = 5/3... :thumbsup
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Furthermore, they are EQUAL. I.e. -25/27x = (-25/27)x Did I say anything about (-25)/ (27x)? Please be sure to read before you post a reply :winkwink: |
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I have been studying cybernetics and maths for a while plus I was making some money tutoring maths for a while too, therefore I know that people usually don't know anything about syntax and you have to try to think ahead.. Allright, here is the solution in steps for both cases anyway: 1) -25/27x + 8/9 = 1/3 -25/27 x = 1/3 - 8/9 x = [(1/3 - 8/9) * 27 ] / (- 25) ---------------------------------------- 2) (-25)/(27x) + 8/9 = 1/3 (-25)/ (27x) = 1/3 - 8/9 -25 = (1/3 - 8/9) * 27x -25 / [(1/3 - 8/9)*27] = x I love to work with numbers .. |
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Quite the group of mathies on this board, lol.
WG |
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What I am trying to say is that even EVERYONE come through the 5 th grade elementary school there is actually VERY FEW that would know how to use brackets once they are out of the school for a while.. It's absolutely natural and everyone have right to forget stuff he doesn't use, but also SHOULD NOT show off something he forgot.. :2 cents: |
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If my calculations are correct, the answer is: 15,21
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be sure to check it on with a calculator. I.e. copy-paste these formulas into http://instacalc.com/ : 1) -25/27*54 2) (-25/27)*54 Let me know if you'll get a different result with one of the formulas above, professor :winkwink: Hint: Both -25/27*54 and (-25/27)*54 ARE ABSOLUTELY EQUAL and they both = -50 :) Furthermore, -25/27 * 0.6 + 8/9 is EQUAL to (-25/27) * 0.6 + 8/9 and it is 1/3 . Surprised? :winkwink: |
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Not too difficult an equation.
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damn, what's wrong with gfy? i feel like i'm back at highschool... :Oh crap...
this thread needs some boobie pics ASAP... |
You guys have done a great job of over complicating a rather simple problem (for a 9th grader). :thumbsup
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[ -25/27x = -25/(27x) ] is the valid statement. I think it's just a syntax thing at this point - and perhaps (-25/27)x is what baddog meant but you're still wrong in what I quoted. No question there. Math is an international language, and parentheses are everything in math... if your elementary math instructors taught you otherwise, you'd do well to write the givers of your early education a strongly-worded letter. :2 cents: |
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-25/27x = -25/(27x) is correct. 1) Try this PHP code if you want: <?php $x = 54; // some sample value echo -25/27*$x . " = " . (-25/27)*$x; ?> You will be surprised when you'll see the result because it will be "-50 = -50" 2) Don't have PHP at your server? Ok, I believe you are able to do this: a) click at http://instacalc.com/ b) copy-paste this into the calculator's box: -25/27*54 c) remember the result (it will be -50) d) copy-paste this into the calculator's box: -(25/27)*54 e) remember the result (it will be -50) f) now compare the results you got in (c) and (e). aren't they equal? (-25/27)x is baddog meant and it IS what he wrote. because: (-25/27)*x = -25/27*x (note 2 ways to check it above) PERIOD. P.S. x = 54 in both samples and it does not belong to {-1, 0, 1} as you stated above. |
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-25/27x is the same as: -25 ---- 27x which you would to type into instacalc as the following: -25/(27*54) and what you would get is not -50 :winkwink: |
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-25/27*54 and it's a same as: -25 ---- 54 27 and that's you have to type in instacalc. But(!!!) if you type there -25/(27*54) it would be -25 ---- 27*54 and it would be -25/(27*x) but NOT -25/27x Haven't you learn this in the 1st or 2dn degree of preliminary school? What's a funny thread :) |
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Yes, you are absolutely correct :winkwink: because you changed the parentheses in the quoted post |
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1) -25/27x = -25 / 27 * x
2) -25/(27x) = -25 / (27 * x) Those are different ones. Because (1) <> (2). |
Simple people !
-25/27x + 8/9 = 1/3 ( original question )
-25/27x + 24/27 = 1/3 ( find a common denominator in this case 27 ) -1/27x = 1/3 ( do a simple subtraction of -25 + 24 = -1 ) -1/27 / 3/1 = x ( separate the x from the equation... -1/1 = -1 and 27/3 = 9 ) -1/9 = x ( now x has been solved ! ) -1/27 * -1/9 = 1/3 ( now the -1/27x is like saying -1/27 * x or -1/27 * -1/9 ) -1/27 / 9/-1 = 1/3 ( invert to cancel out... -1/-1 = 1 and 27/9 = 3 ) 1/3 = 1/3 . |
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But, the part I qouted is quite different from your argument in this thread. Ok, I have to watch my postcount. I will take a break now. |
x = 3/5 :2 cents:
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1 + (0+i1) = 2 which is wrong because the result is also a complex value = 1+i1 <> 2 (since a complex presentation of 2 = 2+i0) Someone would definitely try to say that 1+i1 = 2, but I will insist that 1+i1 <> 2+i0 and this thread will get at least 3 new pages :winkwink: j/k :) |
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0.999 = 1. Hope that helps.
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Just an FYI, about an hour after I posed the question it was revealed to me that the equation above is the actual question. For those using decimals, not applicable . . the test is purely fractions, not decimals. Thanks though. |
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Baddog, listen to the sensible and check no. 68 for a way how to cope with it.. I am off |
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It is 8th grade level. So that would be right. |
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P.S. I had "3" for Math too :) |
This has became a very educational thread.. Never new that there are so many Math genius here:thumbsup
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