Time Travel is Possible....scientific proof!!!

This has been one of the most interesting threads in a while...

http://www.kfcplainfield.com/sound/timetunnel.wav The Time Tunnel Theme Song

Cool...here's another one that I think you should read:
http://gofuckyourself.com/showthread.php?t=454185

..wait.. wait.. I'm getting something..
Oh yeah, no maths or physics in your theories.

false alarm.

(RIL+SOT/2)/MPOR=AAC...



RIL : Rapid Image Processing SOT: Speed Of Thought
MPOR: Manditory Point Of Repetition
AAC: Attracts Asshole Critics who can produce no evidence to the contray either with ot without the quaifications they state is required of my evidence.


This is your brain
This is your brain after my theory:food-smil

It just works Napoleon, you don't even know.

Don't most people call this Deja Vu?

Say hi to Captain Kirk for me........

You give no theory.
I will listen to you when you publish your studies, with accompanying pages of equations and mathematical functions.

Until then you can string things together and call them 'proof' as much as you want.

Pun intended?

again this guy is smoking crack! lol

STP, STOP, I just figured something, it's all wrong, OMG, it's all WRONG !!!

Demonstration:
The coefficients of the power series solutions of certain non-linear
differential equations are generated by convolutions of the preceeding
coefficients. One example is the differential equation

x x'' + a (x')^2 = b (1)

Among the solutions of this equation (with appropriate choices of a,b)
are exp(t), sin(t), cos(t), (A+Bt)^n, A+Bt+Ct^2, and sqrt(A+Bt+Ct^2).
This last function represents the separation between any two objects
in unaccelerated motion. Other solutions include the cycloid relation
for (non-rotating) gravitational free-fall, and the radial distance
of a mass from a central point about which it revolves with constant
angular velocity and radial freedom.

The power series solution of equation (1) can be written

x(t) = c[0] + c[1] t + c[2] t^2 + c[3] t^3 + ...

where the coefficients c[i] satisfy the convolutions

n / b if n = 2
SUM A(k,n-k) c[k] c[n-k] = (
k=0 \ 0 if n > 2

with
A(k,j) = (a-1) j (k-j) + k(k-1)/2

Any choice of c[0], c[1], c[2], and c[3], with c[1]c[2] not zero,
determines the values of a,b and therefore all the remaining
coefficients. There are many interesting things about these sequences
of c[k] values. Focusing on just the sequences with |c[k]| = 1,
k=0,1,2,3, there are obviously 16 possible choices, but only 8 up to
a simple sign change. These 8 can be arranged as four groups of 2:

k I II III IV
--- -------- ---------- --------- ---------
0 1 1 -1 1 1 1 1 1
1 1 -1 1 1 1 -1 1 -1
2 1 1 1 -1 -1 -1 1 1
3 -1 1 1 1 -1 1 1 -1
4 1/2 1/2 3/2 -3/2 0 0 1 1
5 1/2 -1/2 5/2 5/2 4/5 -4/5 1 -1
6 -3/2 -3/2 9/2 -9/2 2/5 2/5 1 1
7 3/2 -3/2 19/2 19/2 -2/5 2/5 1 -1
8 3/8 3/8 133/8 -133/8 -1/2 -1/2 1 1
9 -29/8 29/8 267/8 267/8 1/30 -1/30 1 -1
etc

Yhe coefficients in each group differ only in sign. The coefficients
in groups I and II diverge, and those in group IV are all units. Only
the group III sequences converge. Interestingly, these coefficients
are given very closely by

c[k-1] = 2 exp(ku) sin(kw)

for k>2, where
u = -0.145370157...

/ 1.877672951... for III(a)
w = (
\ 1.263919649... for III(b)

Notice that the two possible values of w sum to 3.1415926...

The integer numerators and denominators of these c[k] sequences also
have many interesting properties. For example, primes p congruent to
+1 (mod 4) first appear in the denominator at c[p], whereas primes
congruent to -1 (mod 4) first appear at c[p^2]. The sequence of
numerators is much less regular

1 -1 -1 1 0 -4 2 2 -1 -1 59 -9 -1 233 8 -934 49 .. etc

Incidentally, the value of b in the ubiquitous equation (1) is
essentially just a constant of integration, and the underlying
relation is the derivitive

x x'' + q x' x'' = 0

where q=3 for unaccelerated separations and q=2 for (non-rotating)
gravitational separations. Isolating q and differentiating again
leads to the basic relation, free of arbitrary constants,

x x' x'' x'''' - x x' (x'')^2 - x (x'')^2 x''' + (x')^2 x'' x''' = 0

Dividing by x x' x'' x''' gives the nice form

x'''' x''' x'' x'
------ - ----- - ---- + ----- = 0
x''' x'' x' x

see what i mean???

I just plugged that into my Transmeta Hyper Accelerator, and wow! I'm posting from the future.

:D

Fassinating Captain!