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Old 11-24-2004, 11:03 PM   #1
DogsandBigCats
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(Pic) You are VERY SMART if you can SOLVE THIS PUZZLE!!!!!



I'm curious to see if anybody here is smart enough to figure out the solution to this. Where does this extra space come when a solid shape is rearranged?!! Please humble me with your replies!
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Old 11-24-2004, 11:04 PM   #2
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Old 11-24-2004, 11:07 PM   #3
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its not an extra blank
its pythagorus
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Old 11-24-2004, 11:07 PM   #4
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well if im wrong, im blaming it on the fact that im about to go to bed (just took my sleeping pill) but is the white space the extra space left over from the red blocks that had to be cut from resizing the shape??
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Old 11-24-2004, 11:08 PM   #5
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The top picture's slop is in a different arc than the bottom pics.

The top arcs inwards and the bottom arcs outwards.
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Old 11-24-2004, 11:09 PM   #6
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The red and green triangles meet at a slightly different angle in each, making up for the amount of space in the missing square.
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Old 11-24-2004, 11:09 PM   #7
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Quote:
Originally posted by fusionx
The top picture's slop is in a different arc than the bottom pics.

The top arcs inwards and the bottom arcs outwards.
You're a genious
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Old 11-24-2004, 11:11 PM   #8
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Old 11-24-2004, 11:11 PM   #9
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It was abducted by aliens but shhh don't tell anybody they are always listening...
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Old 11-24-2004, 11:15 PM   #10
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Quote:
Originally posted by fusionx
The top picture's slop is in a different arc than the bottom pics.

The top arcs inwards and the bottom arcs outwards.
True.
If you copy the top on in Photoshop and place it over the bottom one you will see that they are not the same size...
Different slope at the top.

A^2 + B^2 = C^2 and therefore C^2 will be much bigger if A and B are only slightly smaller becaue they are squared and added.

Goodnite.
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Old 11-24-2004, 11:16 PM   #11
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Actually it has little to do with the slopes and more to do with the direction of the hypotenuses of the triangles and quadrilaterals.

Did this is school and thats about all i remember from the lesson

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Lee
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Old 11-24-2004, 11:31 PM   #12
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Quote:
Originally posted by DogsandBigCats
You're a genious
heh - not by a long shot. I just have a good eye for lines, measurements, angles, etc.

In a different life, I was a high-pressure welder. For some jobs, I'd have a maximum tolerance of 1/64th of an inch. You gotta be able to see that difference without thinking about it.
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Old 11-25-2004, 12:00 AM   #13
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2 different slopes
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Old 11-25-2004, 12:03 AM   #14
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slope = rise/ run

the slopes are the same in each.

just an fyi
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Old 11-25-2004, 12:22 AM   #15
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on the first one the yellow L is on top of the green L, small green triangle on top, large red triangle at the bottom.

on the second one the L blocks are side by side and the triangles switched places.

by moving the yellow L out of place it gives some extra horizontal space for the smaller triangle to reach the full lenght, and by being a bit lower it gives room for the red triangle to reach the full height.
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Old 11-25-2004, 12:27 AM   #16
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Here you go...

http://www.nmt.edu/~armiller/triangles.htm

As i said, it has nothing to do with the slopes more the hypotenuse of the two triangles being used

Regards,

Lee
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Old 11-25-2004, 12:34 AM   #17
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I know alot of 8 year olds that would have solved that within a minute..
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Old 11-25-2004, 12:39 AM   #18
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Quote:
Originally posted by European Lee
Here you go...

http://www.nmt.edu/~armiller/triangles.htm

As i said, it has nothing to do with the slopes more the hypotenuse of the two triangles being used

Regards,

Lee
Good lord..

A direct quote from your example:

"The hypotenuses of triangles A and B have different slopes"

It's the SLOPE of the hypotenuse that makes the difference.

The very next sentence states that they are quadrilaterals, not triangles. They are not triangles.

Pythagoras must be rolling over and over...
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Old 11-25-2004, 04:11 AM   #19
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Quote:
Originally posted by Chupachups
I know alot of 8 year olds that would have solved that within a minute..
And I didn't see you solving it? Must be 7 year old then.
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Old 11-25-2004, 10:10 AM   #20
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that was easy
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Old 11-25-2004, 10:12 AM   #21
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If the search was working, you could see that it was solved on here a few times over the past few years.
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Old 11-25-2004, 10:23 AM   #22
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Fuck rise over run, this can be solved in one line by using pick's theorum

A(P) = I(P) + B(P)/2 - 1

There's always a much more elegant solution :D
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Old 11-25-2004, 10:33 AM   #23
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Quote:
Originally posted by bizmak
And I didn't see you solving it? Must be 7 year old then.
I am baffled. Are you dense? Lack of oxygene while you were born?
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Old 11-25-2004, 11:13 AM   #24
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Quote:
Originally posted by European Lee
Here you go...

http://www.nmt.edu/~armiller/triangles.htm

As i said, it has nothing to do with the slopes more the hypotenuse of the two triangles being used

Regards,

Lee
from the link you posted:

This edge bends downward, so the area of the figure is 32. For the lower figure, the slanting upper edge is also made up of two lines that meet where they touch area C. This edge bends upward so the area of the figure is 33. The difference accounts for the hole.
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Old 11-25-2004, 01:10 PM   #25
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Quote:
Originally posted by DogsandBigCats


I'm curious to see if anybody here is smart enough to figure out the solution to this. Where does this extra space come when a solid shape is rearranged?!! Please humble me with your replies!
This is simple the green and orange match up perfectly on the top.

They don't on the bottom, the green has three pegs over fine, and orange has 2 pegs over five. When you reverse them the third peg on the green creates the hole.
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Old 11-25-2004, 01:13 PM   #26
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Is this a joke?

switch red and green, stack the orange ontop of the green put it together yay!
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