Fatal error: Call to undefined function is_home() - GoFuckYourself.com

bloggerz · 02-20-2011, 05:44 PM

hi looking for some help here!

I'm using this code to display something on the home page only, not on the category, posts, or archives pages.

This is the code:

<?php if(is_home() && $post==$posts[0] && !is_paged()) { ?>
ADVERTISEMENT HERE

<?php } ?>

But when I use that I get this error:

Fatal error: Call to undefined function is_home()

Any help is much appreciated thanks!

BittieBucks Eric · 02-20-2011, 06:26 PM

yes, you're using a function "is_home()" and "is_page()" in an equasion. I don't think you can do that.

HarryMuff · 02-20-2011, 07:08 PM

Quote:

Originally Posted by BittieBucks Eric

yes, you're using a function "is_home()" and "is_page()" in an equasion. I don't think you can do that.

Of course you can, the condition statement expects those functions to return a boolean.

The problem you have is that the functions are not defined. (You need to have the functions included in the php file).

bloggerz · 02-20-2011, 07:11 PM

You have the code? Pls copy andpaste thx

HarryMuff · 02-20-2011, 07:13 PM

Why would I have your code?

brassmonkey · 02-20-2011, 07:40 PM

Quote:

Originally Posted by HarryMuff

Why would I have your code?

FlexxAeon · 02-20-2011, 07:40 PM

is it near the top of the page? maybe you're using it before the functions are called in

fris · 02-20-2011, 08:52 PM

Quote:

Originally Posted by bloggerz

hi looking for some help here!

I'm using this code to display something on the home page only, not on the category, posts, or archives pages.

This is the code:

<?php if(is_home() && $post==$posts[0] && !is_paged()) { ?>
ADVERTISEMENT HERE

<?php } ?>

But when I use that I get this error:

Fatal error: Call to undefined function is_home()

Any help is much appreciated thanks!

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

this should do it.

martinsc · 02-20-2011, 09:17 PM

Quote:

Originally Posted by fris

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

this should do it.

a true ninja

HarryMuff · 02-20-2011, 10:15 PM

That code is disgusting

grumpy · 02-21-2011, 01:32 AM

Quote:

Originally Posted by fris

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

this should do it.

wont solve : function not found.

mlove · 02-21-2011, 02:32 AM

is_home() isn't a native php function. It couldn't ever be, and i'm not even going to begin to explain why.

However, At some point, it's probably been written in some script you previously had.

Are you defining this function elsewhere in your codebase? If so, you'll need to use include() to pull the file that defines the function into the script you're working with. It's kinda like writing something like:

Code:

<? fucking(); ?>

This will not work on it's own, but if you have your fucking() function defined in a file like includes/func.fucking.php:

Code:

<? function fucking() { echo "do the bartman"; } ?>

Then you'll be able to use that function.:

Code:

<? include('includes/func.fucking.php'); fucking(); ?>

and then your code would work. But to save on execution time (opening multiple files takes longer), you could do:

Code:

<?  function fucking() { echo "do the bartman"; } fucking(); ?>

Danmixz · 02-21-2011, 02:49 AM

PHP Code:


			
<?php

$homepage = "/";

$currentpage = $_SERVER['REQUEST_URI'];

if($homepage==$currentpage) {

echo 'Adcode here' ;

}

?>

Zyber · 02-21-2011, 05:37 AM

Quote:

Originally Posted by Danmixz

PHP Code:


			
<?php
$homepage = "/";
$currentpage = $_SERVER['REQUEST_URI'];
if($homepage==$currentpage) {
echo 'Adcode here' ;
}
?>

Why create unnecessary variables - when less can do it?

Code:

<?php
if($_SERVER['REQUEST_URI'] == '/') {
 echo 'Adcode here';
}
?>

fris · 02-21-2011, 08:47 AM

Quote:

Originally Posted by grumpy

wont solve : function not found.

where are you using the code?

i added it to a current theme, and it worked like a charm.

bloggerz · 02-21-2011, 08:08 PM

Quote:

Originally Posted by fris

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

this should do it.

Do i need to add something in functions.php or something?
Im still getting Fatal error: Call to undefined function is_home()

potter · 02-21-2011, 09:35 PM

Quote:

Originally Posted by fris

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

this should do it.

It looks like he wants AND statements, not OR statements?

What I don't get is why you need all the other statements. If it is the home page, then when or why would archive, paged, category, tag, or single ever return? Seems odd to me (though I don't use wordpress a lot).

potter · 02-21-2011, 09:42 PM

Now that I think about it, wouldn't

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

Return the ad on a lot more pages than the home page? You're code is basically saying...

[b]Show the ad if:
• It's the home page
• Or if it's not the archive
• Or if it's not paged
• Or if it's not a category
• Or if it's not a tag
• Or if it's not a single.[b]

So it would display the ad on any page that wasn't the archive for instance. Because with all the "OR" double pipes, only one of those circumstances needs to be true for the ad to display.

fris · 02-21-2011, 10:14 PM

Quote:

Originally Posted by bloggerz

Do i need to add something in functions.php or something?
Im still getting Fatal error: Call to undefined function is_home()

where are you adding is_home to?

fris · 02-21-2011, 10:16 PM

Quote:

Originally Posted by potter

Now that I think about it, wouldn't

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

Return the ad on a lot more pages than the home page? You're code is basically saying...

[b]Show the ad if:
? It's the home page
? Or if it's not the archive
? Or if it's not paged
? Or if it's not a category
? Or if it's not a tag
? Or if it's not a single.[b]

So it would display the ad on any page that wasn't the archive for instance. Because with all the "OR" double pipes, only one of those circumstances needs to be true for the ad to display.

it will only show on the front page.

using that code if i view a category or tag page or full post, it doesnt show the ad.

only on the home, not any paged page2,page3, etc.

bloggerz · 02-22-2011, 12:22 AM

Quote:

Originally Posted by fris

where are you adding is_home to?

An external php file and im calling it through php include

mlove · 02-22-2011, 03:06 AM

you are an idiot.

fris · 02-22-2011, 06:20 AM

Quote:

Originally Posted by bloggerz

An external php file and im calling it through php include

well of course it wont work then ;)

its a wordpress function.

potter · 02-22-2011, 08:07 AM

Quote:

Originally Posted by fris

it will only show on the front page.

using that code if i view a category or tag page or full post, it doesnt show the ad.

only on the home, not any paged page2,page3, etc.

Well, it's not-category, and not-paged. My point was

Why not simply use:

Code:

<?php if (is_home()) {?>

ad here.

<?php } ?>

??

Because using

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

Is exactly the same as putting:

Code:

<?php if (is_home()) {?>

ad here.

<?php } ?>

and

Code:

<?php if (!is_archive()) {?>

ad here.

<?php } ?>

On the same page. So not only will it show up on the home page, but it would want to be shown on any page that ISN'T an archive page.

Maybe I'm not explaining myself, but I just don't understand the point of having alllll those extra OR statements?

fris · 02-22-2011, 09:45 AM

Quote:

Originally Posted by potter

Well, it's not-category, and not-paged. My point was

Why not simply use:

Code:

<?php if (is_home()) {?>

ad here.

<?php } ?>

??

Because using

Code:

<?php if (is_home() || !is_archive() || !is_paged() || !is_category() || !is_tag() || !is_single()) {?>

ad here.

<?php } ?>

Is exactly the same as putting:

Code:

<?php if (is_home()) {?>

ad here.

<?php } ?>

and

Code:

<?php if (!is_archive()) {?>

ad here.

<?php } ?>

On the same page. So not only will it show up on the home page, but it would want to be shown on any page that ISN'T an archive page.

Maybe I'm not explaining myself, but I just don't understand the point of having alllll those extra OR statements?

ya you would still need to have !is_paged() though, cause home is considered page2 page3 of the index

potter · 02-22-2011, 10:19 AM

Quote:

Originally Posted by fris

ya you would still need to have !is_paged() though, cause home is considered page2 page3 of the index

weird... I suppose it'll all make sense if I ever use wordpress again and see the code and the way the system functions.

02-20-2011, 05:44 PM	#1
bloggerz Too lazy to set a custom title Industry Role: Join Date: Dec 2006 Posts: 16,256	Fatal error: Call to undefined function is_home() hi looking for some help here! I'm using this code to display something on the home page only, not on the category, posts, or archives pages. This is the code: <?php if(is_home() && $post==$posts[0] && !is_paged()) { ?> ADVERTISEMENT HERE <?php } ?> But when I use that I get this error: Fatal error: Call to undefined function is_home() Any help is much appreciated thanks! __________________ I SELL ADULT BACKLINKS! Email: eroticweb>gmail SKYPE: gfybloggerz $$$$$ MAKE HUGE MONEY IN CAMS - CLICK HERE $$$$$

02-20-2011, 06:26 PM	#2
BittieBucks Eric Confirmed User Industry Role: Join Date: Aug 2010 Posts: 457	yes, you're using a function "is_home()" and "is_page()" in an equasion. I don't think you can do that. __________________ Bittie Bucks - Upto 70% Revshare - CCBill Cascading Program - 10% Webmaster Referral [email protected] - ICQ - 594415957 Need Content TRASHY CONTENT

02-20-2011, 07:11 PM	#4
bloggerz Too lazy to set a custom title Industry Role: Join Date: Dec 2006 Posts: 16,256	You have the code? Pls copy andpaste thx __________________ I SELL ADULT BACKLINKS! Email: eroticweb>gmail SKYPE: gfybloggerz $$$$$ MAKE HUGE MONEY IN CAMS - CLICK HERE $$$$$

02-20-2011, 07:40 PM	#7
FlexxAeon Confirmed User Industry Role: Join Date: May 2003 Posts: 3,765	is it near the top of the page? maybe you're using it before the functions are called in __________________ flexx [dot] aeon [at] gmail Last edited by FlexxAeon; 02-20-2011 at 07:41 PM..

02-21-2011, 02:32 AM	#12
mlove the guy Industry Role: Join Date: Apr 2005 Posts: 764	is_home() isn't a native php function. It couldn't ever be, and i'm not even going to begin to explain why. However, At some point, it's probably been written in some script you previously had. Are you defining this function elsewhere in your codebase? If so, you'll need to use include() to pull the file that defines the function into the script you're working with. It's kinda like writing something like: Code: <? fucking(); ?> This will not work on it's own, but if you have your fucking() function defined in a file like includes/func.fucking.php: Code: <? function fucking() { echo "do the bartman"; } ?> Then you'll be able to use that function.: Code: <? include('includes/func.fucking.php'); fucking(); ?> and then your code would work. But to save on execution time (opening multiple files takes longer), you could do: Code: <? function fucking() { echo "do the bartman"; } fucking(); ?> __________________ If you won't feel as good, I won't feel as cheap.

02-20-2011, 07:13 PM	#5
HarryMuff Confirmed User Join Date: Dec 2005 Posts: 271	Why would I have your code?

02-20-2011, 10:15 PM	#10
HarryMuff Confirmed User Join Date: Dec 2005 Posts: 271	That code is disgusting

02-21-2011, 02:49 AM	#13
Danmixz Confirmed User Industry Role: Join Date: Sep 2010 Posts: 649	PHP Code: `<?php $homepage = "/"; $currentpage = $_SERVER['REQUEST_URI']; if($homepage==$currentpage) { echo 'Adcode here' ; } ?>` __________________ FFMPEG Hosting with AptHost

02-21-2011, 09:42 PM	#18
potter Confirmed User Industry Role: Join Date: Dec 2004 Location: Denver Posts: 6,559	Now that I think about it, wouldn't Code: <?php if (is_home() \|\| !is_archive() \|\| !is_paged() \|\| !is_category() \|\| !is_tag() \|\| !is_single()) {?> ad here. <?php } ?> Return the ad on a lot more pages than the home page? You're code is basically saying... [b]Show the ad if: • It's the home page • Or if it's not the archive • Or if it's not paged • Or if it's not a category • Or if it's not a tag • Or if it's not a single.[b] So it would display the ad on any page that wasn't the archive for instance. Because with all the "OR" double pipes, only one of those circumstances needs to be true for the ad to display. __________________

02-22-2011, 03:06 AM	#22
mlove the guy Industry Role: Join Date: Apr 2005 Posts: 764	you are an idiot. __________________ If you won't feel as good, I won't feel as cheap.