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Originally Posted by SmokeyTheBear
this one is a good easy one..
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You have twelve coins, eleven identical and one different. You do not know whether the "odd" coin is lighter or heavier than the others. Someone gives you a balance and three chances to use it. The question is: How can you make just three weighings on the balance and find out not only which coin is the "odd" coin, but also whether it's heavier or lighter?
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I have solved this one

Can't say it was easy though. Anyone else?