Are there any mathematicians here?

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  • stocktrader23
    Let's do some business.
    • Jan 2003
    • 18781
    #1

    Are there any mathematicians here?

    Is there anyone that could answer this for me?

    Takes the numbers 1 - 14.

    Now combine them in groups of 8 ie. 12345678, 12345679 etc.

    How many seperate groups of numbers would there be with no 2 groupls containing the same set of 8 numbers?


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    • Stud Money
      So Fucking Banned
      • Sep 2003
      • 3214
      #2
      WTF?

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        • JamesK
          hi
          • Jun 2002
          • 16731
          #3
          no way
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            • BlueDesignStudios
              Confirmed User
              • Feb 2003
              • 9492
              #4


              Hrmmm......

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                • stocktrader23
                  Let's do some business.
                  • Jan 2003
                  • 18781
                  #5
                  It's not a test. I really need the answer.


                  Hands Free Adult - Join Once, Earn For Life

                  "I try to make a habit of bouncing my eyes up to the face of a beautiful woman, and often repeat “not mine” in my head or even verbally. She’s not mine. God has her set aside. She’s not mine. She’s His little girl, and she needs me to fight for her by keeping my eyes where they should be."

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                    • testuser
                      Registered User
                      • Sep 2003
                      • 95
                      #6
                      If I read this right, that would be 14 choose 8.

                      Something like 14! / ( 8! 6!) = 3003.
                      ICQ: 273796889

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                        • Hindsight
                          Confirmed User
                          • Oct 2003
                          • 815
                          #7
                          i think the answer is 14 factorial but not definately sure

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                            • winter
                              Confirmed User
                              • May 2001
                              • 570
                              #8
                              Originally posted by testuser
                              If I read this right, that would be 14 choose 8.

                              Something like 14! / ( 8! 6!) = 3003.
                              yup, this is correct:

                              http://www.google.com/search?sourcei...&q=14+choose+8

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                                • Poo-Chee
                                  So Fucking Banned
                                  • Sep 2003
                                  • 3560
                                  #9
                                  wtf ..

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                                    • testuser
                                      Registered User
                                      • Sep 2003
                                      • 95
                                      #10
                                      Whoa, I didn't know google had a calculator. And it does combinatorics? Sweet.

                                      Quick explanation:
                                      14! is the number of orderings of 14 distinct objects. Say you want to pick 8 out of 14 distinct objects. Then you have 14 ways to pick the first object, 13 ways to pick second object, ... , 7 ways to pick the 8th object = 14*13*...*7 = 14!/6!. But these are non-distinct groups, ie. some of the groups are just ordered in different ways. If you have 8 objects, you can order them in 8! different ways. So then you have 14!/(6!8!). Hope that was somewhat coherent.
                                      ICQ: 273796889

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                                        • fnet
                                          Confirmed User
                                          • Jul 2002
                                          • 1721
                                          #11
                                          do you mean 8 total digits or something weird like that?

                                          Originally posted by stocktrader23
                                          Is there anyone that could answer this for me?

                                          Takes the numbers 1 - 14.

                                          Now combine them in groups of 8 ie. 12345678, 12345679 etc.

                                          How many seperate groups of numbers would there be with no 2 groupls containing the same set of 8 numbers?
                                          the sound of one hand googlewhacking

                                            Comment

                                            • Poo-Chee
                                              So Fucking Banned
                                              • Sep 2003
                                              • 3560
                                              #12
                                              Originally posted by fnet
                                              do you mean 8 total digits or something weird like that?
                                              it's been calculated already..

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