elron

This aint a joke , just read the concept and see for yourself

This will only work on a roulette , and if you come with large ammount of cash from the first place .
Your goal in to win $10 each time , and this is how you're going to do this :

you bet $10 on any 50% spot : red/black , odd/even/ 18/36 . And yeah i know there are some 00 and 000 so the chance is less than 50% but that's insignificant .

If you won , round is over and you start over again with betting $10 .
If you lost , you put double next bet - $20 . if this time you won - the totall ballace of the two bets will be again - $10 proft .
If you lost again , you double the bet again to 40$ , and so on . At the end it is enough to win 1 time from the chain of bets to close the round with $10 profit .

The concept is based on the clue that it is unlikely that you will lose 100 bets in a raw when the chance is ~50% per bet , and as long as you come with enough money to double the next chain bet , you will always win the round with $10 profit .

this will work in theory , but the problem with gamblers is that they get greedy and after they won 30,000$ in the whatever chain bet they will never go back to bet on $10 , they will put the whole $30,000 sum and lose their asses like they always do .