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Discuss what's fucking going on, and which programs are best and worst. One-time "program" announcements from "established" webmasters are allowed.

 
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Old 08-20-2018, 08:30 AM   #1
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A test for stupidity



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Old 08-20-2018, 08:33 AM   #2
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I loved that movie!
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Old 08-20-2018, 08:48 AM   #3
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It's not about the movie itself, not about sexual harassment, not about homos etc. It's about the episode shown on the video. Do you have any comments?
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Old 08-20-2018, 09:03 AM   #4
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Do you have any comments?
Yes. I would have preferred to win a goat if I was playing... I mean, think about it for a moment...

You can't really fuck a car, can you?
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Old 08-20-2018, 11:13 AM   #5
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So no mathematical education in the USA? Are you vegetables?
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Old 08-20-2018, 12:06 PM   #6
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So no mathematical education in the USA? Are you vegetables?
Well Im replying from the UK, not the USA, but I'm genuinely unsure what you are wanting to hear? I've heard of the '3 Door Problem' before, and I am aware that you are supposed to change your mind upon revealing the empty door, but aside from that, what is your point?

Is there a technical detail in the explanation he gives in the clip that is wrong or something?
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Old 08-20-2018, 08:22 PM   #7
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I watched a video of how the theory is proven but forget how they explained it. Just thinking about it most would figure 50/50 if there are two choices left and you pick one.
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Old 08-20-2018, 09:43 PM   #8
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I've heard of the '3 Door Problem' before, and I am aware that you are supposed to change your mind upon revealing the empty door, but aside from that, what is your point?
My point is that you don't have to change your mind at all. The chance is exactly 50% for each of two doors that have left. There is no 66% for the second one.
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Old 08-20-2018, 09:48 PM   #9
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My point is that you don't have to change your mind at all. The chance is exactly 50% for each of two doors that have left. There is no 66% for the second one.
wrong the 66% is correct cause, in the beginning, there was 33% and when he shows you one bad door that gives the other 2 doors a 66% chance of being the right one by eliminating a door.
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Old 08-21-2018, 12:29 AM   #10
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wrong the 66% is correct cause, in the beginning, there was 33% and when he shows you one bad door that gives the other 2 doors a 66% chance of being the right one by eliminating a door.
Two doors can not have 66% chance because... because... 66 + 66 > 100. Go to the school already.

The things are easy:

3 closed doors: 33.3(3)% chance for each
2 closed doors: 50% chance for each
1 closed door: 100% chance

INITIALLY these two doors (actually ANY 2 of 3) together had a 66.6(6)% chance and any other one had 33.3(3)%, so summary it was 100% for 3. When one door was removed from the equation, the probability for the rest two doors has changed. Now it's 50% for each of them, so summary it's still 100%.

You don't have to be Einstein to understand the basics of probability theory. In Soviet Union we learned it in the school at 13-14 year old (7th grade). The makers of that movie are idiots and they make more idiots among those who watch this shit.
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Old 08-21-2018, 12:37 AM   #11
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Two doors can not have 66% chance because... because... 66 + 66 > 100. Go to the school already.

The things are easy:

3 closed doors: 33.3(3)% chance for each
2 closed doors: 50% chance for each
1 closed door: 100% chance

You don't have to be Einstein to understand the basics of probability theory. In Soviet Union we learned it in the school at 13-14 year old (7th grade).
um, but did you go past 7th grade? lol this is a college level class.

https://en.wikipedia.org/wiki/Monty_Hall_problem

Quote:
Most people come to the conclusion that switching does not matter because there are two unopened doors and one car and that it is a 50/50 choice. This would be true if the host opens a door randomly, but that is not the case; the door opened depends on the player's initial choice, so the assumption of independence does not hold. Before the host opens a door there is a 1/3 probability the car is behind each door. If the car is behind door 1 the host can open either door 2 or door 3, so the probability the car is behind door 1 AND the host opens door 3 is 1/3 * 1/2 = 1/6. If the car is behind door 2 (and the player has picked door 1) the host must open door 3, so the probability the car is behind door 2 AND the host opens door 3 is 1/3 * 1 = 1/3. These are the only cases where the host opens door 3, so if the player has picked door 1 and the host opens door 3 the car is twice as likely to be behind door 2. The key is that if the car is behind door 2 the host must open door 3, but if the car is behind door 1 the host can open either door.
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Old 08-21-2018, 12:43 AM   #12
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um, but did you go past 7th grade? lol this is a college level class.

https://en.wikipedia.org/wiki/Monty_Hall_problem
Don't post this bullshit here. This is just a thing which is based on human's psychology and has nothing to do with probability theory (it doesn't change the actual chance). And course there is no mathematical proof of it. So please don't try to look smart by picking up some "smart" quotes from wikipedia. The authors of that movie have tried to do the same and they fucked up.

Wanna look smart? Learn to read the mathematical formulas model: Don't Switch! Why Mathematicians' Answer to the Monty Hall Problem is Wrong - IMA and let me repeat: go to the school already.

Just a quote:

Quote:
It looks as if America is in some very serious trouble!
I'll try to explain it to you on a kiddie level (w/o formulas, since you just don't understand 'em). Look, there are 2 doors left (3rd one is opened and it's empty). Fist one has the price. Now tell me how your decision to chance it to 2nd will teleport the price from 1st to the 2nd one? Do you understand that your decision doesn't change the objects inside the closed doors? Also which one you should consider 1st and which one 2nd? From the left or from the right? Maybe you are Arab and used to count them from right to left? Think about it
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Old 08-21-2018, 12:53 AM   #13
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Don't post this bullshit here. This is just a thing which is based on human's psychology and has nothing to do with probability theory (it doesn't change the actual chance). And course there is no mathematical proof of it. So please don't try to look smart by picking up some "smart" quotes from wikipedia. The authors of that movie have tried to do the same and they fucked up.

you are such a fucking moron that just likes to argue with USA people.. It is why at first i didn't even want to reply.

This video that you posted was about this theory. This is about a game show with 3 doors. The guy knows which one it's behind so when he picks he opens a door he knows it isn't and asks do you want to change.. He didn't have 50% odds cause the guy knew exactly where it was.. Just cause you don't understand this doesn't make you right dude.

Quote:
mathematical proof
lol this isn't about a math question cause it's a game show thing that is not random. the game show guy knows where the car is..

haha I'm done.. like how you didn't answer if you went past 7th grade.. cause you act like a 6th grader yelling at people that don't agree with you.
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Old 08-21-2018, 12:59 AM   #14
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you are such a fucking moron that just likes to argue with USA people..
That's not my problem what your education sucks and that's why you are using Russian rockets in the 21st century. I'll give you the same link again: Don't Switch! Why Mathematicians' Answer to the Monty Hall Problem is Wrong - IMA

There is a good explanation why you post bullshit and there is a mathematical proof of it. Learn to read math formulas and come back later.

Once again the so-called "Monty Hall Problem" has nothing to do with mathematics and probability theory. It's about humans psychology. I can show you the programs that can "read your mind" and guess which side of a coin you have imagined in your head. And in most cases it will win you using the statistics of your previous decision (actually it uses a very simple formula). But you can easily level your chances to 50/50 if you won't imagine the coin, but just use a real one instead. The program will be totally confused.

In case of "Monty Hall Problem" with two remaining doors the best option will be... to use a coin. Because there is a 50% chance that the prize is behind the 1st door (from left of from right - you decide) and 50% is that the prize is behind the 2nd door (from left or from right). If you're an European, you will count the doors from left to right, if you are an Arab or a Jew, you will count them from right to left. Changing your mind will not teleport the prize from left door to the right one or vice versa. The prize will still be there where it was before the empty 3rd door was opened. Because when the 3rd door was excluded from the equation, you have only two doors and there is no 66.6(6)% chance for one of them and 33.3(3)% for another. Both have absolutely the same chance and the sum of all chances can not be more than 100 (at least in our University).
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Old 08-21-2018, 02:39 AM   #15
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If the question is, that the car is behind which door (from the remaining two), then the probability is 50-50.

BUT, the question here is: Do you have more chance to win if you switch or if you stay with your first choice? In this case switching means 66.6 and staying 33.3.

So you are both right at some point. That's why it is a paradox.

I think this pic helps to understand.
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Old 08-21-2018, 03:16 AM   #16
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BUT, the question here is: Do you have more chance to win if you switch or if you stay with your first choice? In this case switching means 66.6 and staying 33.3.
O'rly? Now please give me the mathematical explanation for this phenomena of teleportation. How exactly the other door got 2x times more chances when you have changed your mind? Some magic happened? Gandalf has moved the diamond to another cup? A quantum teleportation maybe?

You know what? You will never give it to me, because there is no mathematical formula for that. Even a senile Monty Hall was unable to prove it with formulas, because of Alzheimer. Wanna prove that I'm wrong? Just show me the formulas! That's so easy, ah?

It doesn't matter if you have changed your mind or not, both doors will sill have a 50% chance. And it doesn't matter that the 3rd door is opened and empty. The probability was simply redistributed. That's all that have changed, because one variable was taken out from the formula. With 3 rooms it was 100/3=33.3(3) (the formula is a+b+c=100), now it's 100/2=50 (the formula is a+b=100). Your decision does not affect the expected value. Mathematically. And this is the very basics of math.

P.S. The picture you have posted above it stupid as fuck. The diamond is always in the 1st cup there. Now re-draw it like it's in the 2nd or 3rd cup. And add to it a variant where the opened empty cup was #1, #2 and #3 for each case. You will see that in all cases, the probability to find a diamond under one of 2 remaining cups is 50% and it does not matter if you have changed your mind or not. If you want, I can redraw this picture to "prove" that changing your mind loses 2 times of 3. And you will see that probability of success is not 2/3 but only 1/3 (in fact it's 50%, because (2/3+1/3)/2=0.5). That's in case if you are used to learn math by comics, not by formulas...
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Old 08-21-2018, 03:25 AM   #17
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O'rly? No please give me the mathematical explanation for this phenomena of teleportation. How exactly the other door got 2x times more chances after you have changed your mind?

You know what? You will never give it to me, because there is no mathematical formula for that. Wanna prove that I'm wrong? Just show it!

It doesn't matter if you have changed your mind or not, both doors will sill have a 50% chance. And it doesn't matter that the 3rd door is opened and empty. The probability was simply redistributed. That's all that have changed, because one variable was taken out from the formula. With 3 rooms it was 100/3=33.3(3) (the formula is a+b+c=100), now it's 100/2=50 (the formula is a+b=100). Your decision does not affect the expected value. Mathematically. And this is the very basics of math.
The question is still not the probability of where the car is from the two remaining doors, that would be 50-50 for sure, you are right.
The question is the probability of winning if you switch or not, and the picture I sent above explains this clearly. It's not basic math
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Old 08-21-2018, 03:32 AM   #18
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So the key here is the extra help you get from the anchorman.
If you choose the car at the first place (1/3) and he opens a door with goat) then switching means loosing, staying means winning.
But if you choose a goat (2/3) and he opens the other door with a goat then switching means winning and staying means loosing.
So staying (1/3), switching (2/3).
You have 66.6% chance to win if you switch and 33.3% to win if you stay.
Again, extra info you get, changes the odds.
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Old 08-21-2018, 03:36 AM   #19
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The question is the probability of winning if you switch or not, and the picture I sent above explains this clearly.)
No it does not, because the picture shows only 1 of 3 possible variants, in other variant it will be a loss and it will "prove" that changing your mind makes your chances as low as 1/3. Let me quote myself:

Quote:
The picture you have posted above it stupid as fuck. The diamond is always in the 1st cup there. Now re-draw it like it's in the 2nd or 3rd cup. And add to it a variant where the opened empty cup was #1, #2 and #3 for each case. You will see that in all cases, the probability to find a diamond under one of 2 remaining cups is 50% and it does not matter if you have changed your mind or not. If you want, I can redraw this picture to "prove" that changing your mind loses 2 times of 3. And you will see that probability of success is not 2/3 but only 1/3 (in fact it's 50%, because (2/3+1/3)/2=0.5). That's in case if you are used to learn math by comics, not by formulas...
Your picture and the whole "Monty Hall Problem" works only if the diamond in the 1st cup (we assume it can be in any one of 3, right?). But how it will change if it will be in the 2nd or 3rd one? Try to redraw that stupid picture in your head and you'll see that it does not work anymore
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Old 08-21-2018, 03:38 AM   #20
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But if you choose a goat (2/3) and he opens the other door with a goat then switching means winning and staying means loosing.
Why??? So if you have initially chosen the door with goat and then changed your mind, the goat will be teleported to a new door? Wow!!! A formula please...
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Old 08-21-2018, 03:45 AM   #21
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I'd still prefer to fuck one of the goats...
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Old 08-21-2018, 03:47 AM   #22
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Why??? So if you have initially chosen the door with goat and then changed your mind, the goat will be teleported to a new door? Wow!!! A formula please...
Lol, I am really happy I understand both viewpoint crystal clear

I choose a goat initially, the guy helps me by removing one goat, I change, I win/I stay, I loose.
Nothing to do with teleportation.
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Old 08-21-2018, 03:48 AM   #23
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I'd still prefer to fuck one of the goats...
but that's not the question too
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Old 08-21-2018, 03:51 AM   #24
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Old 08-21-2018, 03:52 AM   #25
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but that's not the question too
Yeah, but this thread is making me horny...
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Old 08-21-2018, 03:57 AM   #26
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I think the debate is closed with this video, thanks CS
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Old 08-21-2018, 04:31 AM   #27
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I choose a goat initially, the guy helps me by removing one goat, I change, I win/I stay, I loose.
No, you don't understand how it works. The guy really helps you by removing the empty value (he initially knew it's empty). So he just redistributed the probability from a+b+c=100 to a+b=100. After that you have a 50% chance instead of 33.3(3)%. So mathematically you just have a set of new parameters (a new task).

Now surprise (opening you a secret of the magic)! If fact you had a 50% chance from the beginning. Because only 2 doors count (the one with the prize and one w/o it) because the 3rd door does not participate in the game. One of two knowingly empty doors will be removed from the game by the host. It doesn't matter which exactly door did you choose, because the dude will remove the remained empty one anyways (there is always at least one room will be empty). So you start the game with 2 doors (not with 3) because the 3rd one was a fake butaphory. In fact you already have 50/50 chance and it doesn't matter will you change your mind or not.

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I think the debate is closed with this video
Of course not. Does the video explains that there is no 3rd door at all? Formally there are really 3 doors, but one empty door will be removed from the game right at the beginning and there will be only a door with a prize and one door which is empty. There are two doors are available for you initially. The 3rd one is a mirage (it's a fake). The game host tells you: choose one of 3 doors and I will remove one of the reminded ones which knowingly has no prize inside, because I know it's empty, so you will stay will two doors: one with a prize and one w/o it (a 50/50 chance) Would you like to change the door? You may say: so why there where 3 doors initially? And you've get his answer: to confuse you, moron!

A stupid show for silly people. As about Monty Hall, so he was just a senile Alzheimer old man. I don't understand the people who still believe in Voodoo magic and can be tricked by a hocus-pocus which was worked before A.D...

P.S. As I said above, this "phenomena" has nothing to do with mathematics (everybody who has studied it in the school knows the chance is 50/50). It is a trick on human's psychology. A very simple trick which works on silly people only. Everybody who has a bit of logic will recognize the "catch" from the beginning. Some people think that women can't think logically. So yesterday I have shown that video to my wife and asked what she thinks. She answered right immediately: they are idiots, the chance is 50/50, because there is only 2 rooms - one with a prize and another one w/o it.

And she was right. Doesn't matter how many empty rooms there were before if all of them were excluded from the equation by the game host, because he has left only two and only one of them has a prize. You can change your mind a million times, but the chance will be 50% anyways.
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Old 08-21-2018, 05:02 AM   #28
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So you still have the same opinion after the card explanation?
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Old 08-21-2018, 05:14 AM   #29
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So you still have the same opinion after the card explanation?
Yes, of course. Because it's a different case. The trick is similar but not the same. In the movie scene the "teacher" has removed an empty door (he knew it's empty) from the beginning and left 50/50 chance to his student, who (because he's an imbecile I think) said that one door now has 66% and other 33% (which one and why the hell???) Isn't that stupid, ah?

Give me a card deck and I'll show you something you will never been able to explain. It will be your deck, you will control it (hold in your hands, shuffle it etc). You will imagine some card in your head and I'll show it to you. Magic? Mathematics? Card counting (ah, I won't even watch when you shuffle 'em)? Long sleeves? No, I will do it in a t-shirt or even w/o it (as you want).

The answer is: manipulation. Not a manipulation with cards. A manipulation with your mind. You will think that you control everything, that you imagine the card etc, but in fact, you will do what I want. So all these Monty Hall tricks are too lame for me. When you see 3 doors, I see only two of them and I do count the expected value (which actually can be "calculated" even by a little kid). Maybe that's why I've decided to be a coder? ;)
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Old 08-21-2018, 06:01 AM   #30
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Yeah, but this thread is making me horny...


Are the goats dressed all sexy like this one, or are they just buck ass naked?
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Old 08-21-2018, 06:51 AM   #31
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Yes, of course. Because it's a different case. The trick is similar but not the same. In the movie scene the "teacher" has removed an empty door (he knew it's empty) from the beginning and left 50/50 chance to his student, who (because he's an imbecile I think) said that one door now has 66% and other 33% (which one and why the hell???) Isn't that stupid, ah?

Give me a card deck and I'll show you something you will never been able to explain. It will be your deck, you will control it (hold in your hands, shuffle it etc). You will imagine some card in your head and I'll show it to you. Magic? Mathematics? Card counting (ah, I won't even watch when you shuffle 'em)? Long sleeves? No, I will do it in a t-shirt or even w/o it (as you want).

The answer is: manipulation. Not a manipulation with cards. A manipulation with your mind. You will think that you control everything, that you imagine the card etc, but in fact, you will do what I want. So all these Monty Hall tricks are too lame for me. When you see 3 doors, I see only two of them and I do count the expected value (which actually can be "calculated" even by a little kid). Maybe that's why I've decided to be a coder? ;)
It's nothing to do with Jedi mind tricks, it's probability. It's okay if you don't agree with a theory but "said that one door now has 66% and other 33% (which one and why the hell???)" you just don't get it
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Old 08-21-2018, 07:28 AM   #32
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My point is that you don't have to change your mind at all. The chance is exactly 50% for each of two doors that have left. There is no 66% for the second one.
Nope sorry that's incorrect. The movie clip does a great job of explaining it. Here's a more detailed explanation though: https://betterexplained.com/articles...-hall-problem/
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Old 08-21-2018, 07:35 AM   #33
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Yes, that's the one.
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Old 08-21-2018, 08:20 AM   #34
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Nope sorry that's incorrect. The movie clip does a great job of explaining it. Here's a more detailed explanation though: https://betterexplained.com/articles...-hall-problem/
That's nothing but just blah-blah (no single formula). I have explained it above on a childish level. In this formula: a+b=100 both doors have a 50% probability (in mathematics we call these variables equiprobable events). There is no "c" variable, because the 3rd door (it could be located at any of 3 places) was already removed from the equation (watch the movie scene again please) and this fact doesn't add any additional weight to "a" over "b". There are still only 2 (two) doors. One of them has a prize, the other one has not. Change your mind or not, but the prize will not teleport anywhere.

Why you people are so easy to be tricked and manipulated? Do you believe in Santa, Jesus Christ or flat Earth maybe?

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It's nothing to do with Jedi mind tricks, it's probability. It's okay if you don't agree with a theory but "said that one door now has 66% and other 33% (which one and why the hell???)" you just don't get it
It was exactly what I say. Remember the picture you have posted above? It was a pure manipulation because in all 3 sequences the diamond was in the 1st cup. Now move it to the 2nd and 3rd one and this "proof" will stop working. The picture authors simply manipulate with your mind to give you an illusion they are right, because they "forgot" to show you two other variants (actually they did the say as TV propaganda here or there does every day - RT, CNN, FOX, BBC etc). Change the initial parameters (the diamond's position) and the "proof" will fall apart just like a card house. Actually that's why there are only videos and pictures for the Monty Hall trick but no single mathematical proof with formulas. Pics and videos do really work for silly and uneducated people, but formula is something where the lie can be caught just easily.

If you guys want, I can make an online simulator of this game and you'll see that all your "explanations" are just a bullshit for redneck housewives. I can post you a ton of videos that also "prove" that planet Earth is flat. I can even "prove" that Jesus Christ is really a son of the God and the God's reincarnation on Earth. I will use the Occam's razor to "prove" the God's existence (which actually it was created for) and course I can "prove" the existence of Santa Claus.
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Old 08-21-2018, 09:07 AM   #35
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this theory is flawed.

now there are 50/50 chance of winning.
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Old 08-21-2018, 09:19 AM   #36
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Only if you omit the previous data is it 50/50. The data is not irrelavant and the video CS posted gives a good explanation of why. It is important to remember that your initial odds of choosing the correct door was 1/3. So forget about revealing the one door and just consider the other two doors as one.
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Old 08-21-2018, 09:31 AM   #37
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It is important to remember that your initial odds of choosing the correct door was 1/3.
It was not. Because the 3rd door was a fake. Doesn't matter which door you have chosen, your "math teacher" has removed the empty one form the equation at the beginning and you have only two rooms to choose. In fact the 3rd door has never existed at all (it was not a part of the equation). So you initially had a 50/50 chance and it hasn't changed (once again: because one of 3 doors was a virtual fake - a decoration). So where the people get 66, which is actually 67 because 66.6(6) is always rounded to 67, I don't understand. I'm used to look at the real facts and I don't give my attention to distracting elements.
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Old 08-21-2018, 10:03 AM   #38
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yes its about Red or Black
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Old 08-21-2018, 10:03 AM   #39
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It was not. Because the 3rd door was a fake. Doesn't matter which door you have chosen, your "math teacher" has removed the empty one form the equation at the beginning and you have only two rooms to choose. In fact the 3rd door has never existed at all (it was not a part of the equation). So you initially had a 50/50 chance and it hasn't changed (once again: because one of 3 doors was a virtual fake - a decoration). So where the people get 66, which is actually 67 because 66.6(6) is always rounded to 67, I don't understand. I'm used to look at the real facts and I don't give my attention to distracting elements.
The door was not fake because it was a probable choice and it still exists even though it has been opened it cannot be taken away from the equation. If you started with three doors you still remain with three doors even if one is open.
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Old 08-21-2018, 11:58 AM   #40
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It gave me a headache but I got it in the end - CyberSEO you are wrong - I see what you are saying but it's just one of those strange things that maths throws up occasionally...
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Old 08-21-2018, 12:17 PM   #41
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It gave me a headache but I got it in the end - CyberSEO you are wrong - I see what you are saying but it's just one of those strange things that maths throws up occasionally...
Exactly

And the picture I posted above works even if the diamond is under cup 2 or cup 3.
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Old 08-21-2018, 12:23 PM   #42
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It gave me a headache but I got it in the end - CyberSEO you are wrong - I see what you are saying but it's just one of those strange things that maths throws up occasionally...
I also see what you say and I have to admit that this thing will really work with some initial assumptions (at least 4 of them). Yes, I was thinking about it for a while and I see the way it will be working, but once again: all the conditions must be applied. At least I can describe these conditions by straight math formulas (not stupid videos or comics for imbeciles).

The key thing there is when exactly you've made a choice, did you tell about it to the game host who knows where the prize is and who wants to help you to reduce the probability from 1/3 to 1/2 and he will never remove the door with the prize. If all these things are correct, yes it will work, because the second iteration uses the merged variables (so variable "c" was not removed but it was added to "b"):

1st iteration: a+b+c=100
2nd iteration: a+d=100, where d=b&c, "a" and "d" have 50/50 chance, but with an amendment that "d" is "b" and "c" combined together.

Yes, in this case it will work. I do agree.
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Old 08-21-2018, 07:39 PM   #43
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yup that video explains it perfectly. The card trick they showed really makes the point as to why you should switch
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Old 08-21-2018, 08:38 PM   #44
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Two doors can not have 66% chance because... because... 66 + 66 > 100. Go to the school already.



In Soviet Union we learned it in the school at 13-14 year old (7th grade).
Is that part of middle school grifter training in "Soviet Union"?
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Old 08-21-2018, 11:23 PM   #45
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Is that part of middle school grifter training in "Soviet Union"?
"grifter"? You mean scammers like Christopher Mallick and his ePassporte? Maybe someone like the owner of ProAdult.com who has lost all the affiliate earnings in casino? Maybe iBill? Or the thieves from Manwin? I don't think these were learning something in the Soviet schools. I guess they all have the US education. While you scam in the Internet, the people with the Soviet education make rockets to send your "astronauts" to the outer space, because if you start making your own challengers and colombias again, you will kill lots of people. A grenade in ape's hand is not good. Nobody want's it.

Here is the map of the places the internet scammers are located in, according to the Microsoft intell info (Windows 10 sees everything you do at your computer):



And the article for you: 10 High-Risk Online Fraud Countries That You Should Monitor - The USA has more e-commerce fraud than Nigeria. Do you see Russia there? Personally I see the USA with a bronze medal... right after Latvia and Egypt. How come?



The USA has more e-commerce fraud than Nigeria. Wow! A new level has been reached. Congrats on that! Do you guys learn the Internet fraud in the school?
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