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PussyTeenies · 01-23-2006, 04:22 AM

assuming xxx.html is to be replaced by yyy.html

for i in $(ls -1 *);do sed 's/xxx.html/yyy.html/g' $i ; done

for i in $(ls -1 */*);do sed 's/xxx.html/yyy.html/g' $i; done

01-23-2006, 04:22 AM
PussyTeenies Confirmed User Join Date: Feb 2005 Location: Haarlem and Amsterdam, capital of the porn world ;-) Posts: 6,496	assuming xxx.html is to be replaced by yyy.html for i in $(ls -1 );do sed 's/xxx.html/yyy.html/g' $i ; done for i in $(ls -1 /*);do sed 's/xxx.html/yyy.html/g' $i; done __________________ Need adult hosting? Contact us! WARM Hosting Need an IT solution? or someone to check your site and security? Nossie - IT Professional