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Originally Posted by detoxed
Well do the odds.... $1000 for every win. That means at a $100k table, you have to win 64times before losing 7 in a row. Say to win 64 times, you have to go through 140 games (green numbers and all, its not 50/50). So what are the chances in 140 games, how many 7 will lose in a row?
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Believe me, I was just like you 2 years ago - tried to attack this problem with everything I had
when you play 140 games, you will get 7 blacks/red in a row exactly 1.09375 times (140 turns / getting is every 128th turn - 2^7)
and it's too much
You can sit one night and make good profit, but if you sit with this system for one month you'll lose