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Old 01-16-2005, 09:04 PM  
Varius
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Join Date: Jun 2004
Location: New York, NY
Posts: 6,890
Quote:
Originally Posted by sharpx9
Four men want to cross a bridge. They all begin on the same side. It is night, and they have only one flashlight with them. At most two men can cross the bridge at a time, and any party who crosses, either one or two people, must have the flashlight with them.
The flashlight must be walked back and forth: it cannot be thrown, etc. Each man walks at a different speed. A pair must walk together at the speed of the slower man. Man 1 needs 1 minute to cross the bridge, man 2 needs 2 minutes, man 3 needs 5 minutes, and man 4 needs 10 minutes. For example, if man 1 and man 3 walk across together, they need 5 minutes.
How can all four men cross the bridge in 17 minutes?
man 1 and man 2 walk across together. this is 2 minutes
man 2 walks back alone with flashlight, we are at 4 minutes now
man 3 and man 4 walk across together, upto 14 mins now
man 1 comes back alone with flashlight, 15 mins
man 1 and 2 go across, upto 17 mins

total: 17 minutes

At first I kept getting stuck at 19 minutes, by sending man 1 and 4 across as step 1..but with a bit of trying diff combinations, I got it
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