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Old 12-17-2004, 03:09 PM  
ytcracker
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Join Date: Dec 2002
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Quote:
Originally posted by MaskedMan
I think not.
silvertabs explanation is probably as simple as it gets

your choice is not 50/50

your initial choice was based on 3 boxes

the host will always show you that one box is empty

Quote:
Let's take a look at the 3 cases again LOL
1 = prize, 0 = no prize

CASE 1:
A B C
1 0 0

You pick A, the host open eighter B or C...you stay with your choice, you win....you switch, you lose... ONLY CASE WHERE YOU WILL WIN

CASE 2:
A B C
0 1 0

You pick A, the host open C....you switch,
YOU WIN...you stay with your choice YOU LOSE

CASE 3:
A B C
0 0 1

You pick A, the host open B....you switch,
YOU WIN...you stay with your choice YOU LOSE
this makes perfect sense

do not think of this in terms of only two boxes
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