Quote:
Originally posted by punkworld
But those 4 options don't have equal chances. Just because they're all there, doesn't mean they're all just as likely.
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For one to be more likely than the other, wouldn't it's result have to be more frequent in the pool? I mean, let's take a six sided die. Let's say it has 1, 2, 3, 4, 5 and 5. No six on this dice.
Total possible results= 6.
Chance of a 1 coming up = 1 in 6
....
Chance of a 4 coming up = 1 in 6
Chance of a 5 coming up = 2 in 6 or 1 in 3.
In the 3 box situation we're dealing with, there is only one possible combination for each outcome, and therefore they are just as likely as eachother, aren't they?