Thread: creating a directory file..
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Old 05-17-2004, 05:39 PM  
NaughtyJenn
Confirmed User
 
Join Date: Apr 2003
Location: Ontario Canada
Posts: 7,355
Quote:
Originally posted by beergood
prog:
----

#!/usr/bin/perl

$path = @ARGV[0];

system("ls -al $path > output.txt");

--

execution

./program.pl /path/you/want/to/list/

should work.
dont have shell access though.. no ssh on the server..
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