Quote:
Originally posted by WarChild
Alright.
Three men are at a convention and are staying in the same hotel room. The room cost $15 for the night so each of the three men pays $5.
Later, the hotel owner remembers that because of the convention, the room should have cost the men only $10 in total. The owner gives the bell hop five $1 bills and asks the bell hop to take it to the men.
The bell hop figures there is no way to divide five bills evenly amongst three men .. So he decides to keep two of the 1 bills for himself, and returns to each man a $1 bill.
Now, the room cost $15 originally, or $5 for each man. However with the $1 bill back in each of the three mens pockets, each man has in affect only paid $4 for the room.
$4 X 3 = $12 ... Plus the $2 the bellhop keeps .. That adds up to $14 ... There were however $15 originally, in the begining of this story.
Where is the missing dollar?
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Ah this question only fools an idiot.
It's not a question of math, but a question of number.
If you do the math of course it would add up wrong, but if you count the money out, it's all there.
5 dollars each per room that ='s 15
The bell hop gets 5 from from the manager. At this point there is 15 dollars, 10 for the room, 5 in the bell hops hand.
He then goes to the room and there are 3 men there.
10 dollars at the front counter.
He hand a dollar to each of the 3 men. That makes 11, 12 and 13.
Then 2 dollars in his pocket make 15.
The way the math works out you count the 12 twice.
Follow the money not the math.
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