I need help with a site. I will pay 25 usd to the first person who can help me with 1 line of code.
Here is a snippet of the code:
Code:
<?php foreach ($query->result() as $row):?>
<!DOCTYPE html>
<html lang="en">
<head prefix="og: http://ogp.me/ns# fb: http://ogp.me/ns/fb# website: http://ogp.me/ns/website#">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=3.0, user-scalable=yes" />
<title><?php echo $row->titulo; ?> - <?php echo $ciudad; ?><?php echo $this->codigo; ?> - <?php echo $this->categoria_model->ObtenerNombreCategoria($row->categoria);?> - <?php echo $this->website; ?>
</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta name="keywords" content="<?php echo dinv_extracto(strip_tags($row->descripcion),10); ?>">
<meta name="description" content="<?php echo dinv_extracto(strip_tags($row->descripcion),40); ?>">
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>"/>
The line:
<meta property="og:image" content="<?php echo base_url(); ?>upload/gallery.php?imagen=<?php echo $fila['imagen1']; ?>"/>
when I run it through facebook debugger tool it only sees:
<meta property="og:image" content="http://www.hiphopfind.com/upload/gallery.php?imagen=">
It cant pick up the <?php echo $fila['imagen1']
Can someone tell me what line of code I can place before this for it to be able to read this?
I will send 25usd to first person who can help me with this issue.
Thanks In advance!
If you need contact me on skype to fix go: Skype: seanleebiz