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Old 01-31-2008, 05:02 AM  
RedShoe
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Quote:
Originally Posted by ADL Colin View Post
You can use simple algebra and be accurate. Just assume all the .33333's are repeating.

Let x = .33333+.33333+.33333 = 3(.33333...)
10x = 3*(3.33333) ; multiply both sides by 10.

Subtract the first term from the first and solve for x.

(10x-x) = 3*(3.33333)-3*(.33333)
9x = 3(3.33333-.33333)
9x = 3 (3)
9x = 9
x = 1
Actually, Colin...

o y = r cubed over 3. And if you determine the rate of change in this curve correctly, I think you'll be pleasantly surprised. Derivative dy = 3 r squared dr over 3, or r squared dr, or......

Colin? Figure this one out genius.

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