View Single Post
Old 01-13-2007, 03:44 AM  
Myst
Confirmed User
 
Join Date: Feb 2004
Location: Alberta, Canada
Posts: 4,708
Quote:
Originally Posted by websiex View Post
You get the 8 shots you take and divide them by the automatic 20%[.2](heads) that is going to take place. Now, you want to see how many times that 20% (out of 8) is going to happen exactly 2 times, so you set it equal to 2. So you get:

8/.2=2
40=2
40=40
2/40= .05

.05%
wtf
the odds of getting exactly 2 is 2 times success and 6 times failure
thats .8^6 * .2^2
Myst is offline   Share thread on Digg Share thread on Twitter Share thread on Reddit Share thread on Facebook Reply With Quote